मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Write ∫cotx dx.

Advertisements
Advertisements

प्रश्न

Write `int cotx  dx`.

बेरीज
Advertisements

उत्तर

`int cotx . dx`

= `int cosx/sinx . dx`

`d/dx sin x` = cos x

= `int ((d/dx sin x)/sin x . dx)`

= log (sin x) + c

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2022-2023 (March) Official

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Integrate the functions:

sin (ax + b) cos (ax + b)


Integrate the functions:

`1/(cos^2 x(1-tan x)^2`


Integrate the functions:

`sqrt(sin 2x) cos 2x`


Integrate the functions:

`1/(1 + cot x)`


\[\int e^x \sqrt{e^{2x} + 1} \text{ dx}\]

\[\int\sqrt{2 x^2 + 3x + 4} \text{ dx}\]

Write a value of\[\int\frac{\sin x + \cos x}{\sqrt{1 + \sin 2x}} dx\]


Evaluate the following integrals:

`int (cos2x)/sin^2x dx` 


Evaluate the following integrals:

`int(2)/(sqrt(x) - sqrt(x + 3)).dx`


Integrate the following functions w.r.t. x : `sqrt(tanx)/(sinx.cosx)`


Integrate the following functions w.r.t. x:

`(sinx cos^3x)/(1 + cos^2x)`


Evaluate the following : `int (1)/sqrt(2x^2 - 5).dx`


Evaluate the following : `(1)/(4x^2 - 20x + 17)`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2sinx).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2 sin2x + 4cos 2x).dx`


Choose the correct options from the given alternatives :

`2 int (cos^2x - sin^2x)/(cos^2x + sin^2x)*dx` =


Choose the correct options from the given alternatives :

`int (e^(2x) + e^-2x)/e^x*dx` =


Evaluate `int (3"x"^3 - 2sqrt"x")/"x"` dx


Evaluate the following.

`int "x" sqrt(1 + "x"^2)` dx


Evaluate the following.

`int 1/("a"^2 - "b"^2 "x"^2)` dx


Evaluate the following.

`int 1/(7 + 6"x" - "x"^2)` dx


If f '(x) = `1/"x" + "x"` and f(1) = `5/2`, then f(x) = log x + `"x"^2/2` + ______


To find the value of `int ((1 + log x) )/x dx` the proper substitution is ______.


Fill in the Blank.

`int 1/"x"^3 [log "x"^"x"]^2 "dx" = "P" (log "x")^3` + c, then P = _______


Evaluate: `int log ("x"^2 + "x")` dx


`int  ("e"^x(x - 1))/(x^2)  "d"x` = ______ 


`int cos^7 x  "d"x`


`int x^3"e"^(x^2) "d"x`


`int(5x + 2)/(3x - 4) dx` = ______


If `tan^-1x = 2tan^-1((1 - x)/(1 + x))`, then the value of x is ______ 


`int(7x - 2)^2dx = (7x -2)^3/21 + c`


`int dx/(2 + cos x)` = ______.

(where C is a constant of integration)


`int cos^3x  dx` = ______.


Evaluate `int_(logsqrt(2))^(logsqrt(3)) 1/((e^x + e^-x)(e^x - e^-x)) dx`.


`int secx/(secx - tanx)dx` equals ______.


Evaluate `int1/(x(x - 1))dx`


`int x^3 e^(x^2) dx`


Evaluate `int (1+x+x^2/(2!)) dx`


`int "cosec"^4x  dx` = ______.


Evaluate the following.

`int "x"^3/sqrt(1 + "x"^4)` dx


Evaluate `int 1/(x(x-1))dx`


Evaluate the following.

`int1/(x^2 + 4x - 5)  dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)dx`


Evaluate the following.

`int1/(x^2 + 4x-5)dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x). 


Which substitution is appropriate for \[\sqrt{\frac{\mathrm{a}-x}{\mathrm{a}+x}}\] or \[\sqrt{\frac{\mathrm{a}+x}{\mathrm{a}-x}}\]?


For \[\sqrt{\frac{x-\alpha}{\beta-x}}\] or \[\sqrt{(x-\alpha)(\beta-x)}\], where \[\beta>\alpha\], which substitution is used?


How should a substitution be chosen?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×