मराठी

I F ∫ E X ( Tan X + 1 ) Sec X D X = E X F ( X ) + C , T H E N W R I T E T H E V a L U E \Of F ( X ) .

Advertisements
Advertisements

प्रश्न

\[If \int e^x \left( \tan x + 1 \right)\text{ sec  x  dx } = e^x f\left( x \right) + C, \text{ then  write  the value  of  f}\left( x \right) .\]

 

 

बेरीज
Advertisements

उत्तर

\[\int e^x \left( \tan x + 1 \right) \text{ sec  x  dx} = \int e^x \left( \tan x\sec x + \sec x \right) dx\]
\[ = \int e^x \left( \sec x + \tan x\sec x \right) dx\]
\[\text{ Consider}, f\left( x \right) = \sec x,\text{  then f}^{ ' } \left( x \right) = \tan x\sec x\]
\[\text{ Thus , the  given  integrand  is  of  the  form e}^x \left[ f\left( x \right) + f^{ '} \left( x \right) \right] . \]
\[\text{ Therefore,} \int e^x \left( \tan x + 1 \right) \text{ sec  x  dx} = \sec x \text{ e}^x + C\]
\[\text{ Hence,} f\left( x \right) = \sec x .\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 18: Indefinite Integrals - Very Short Answers [पृष्ठ १९८]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 18 Indefinite Integrals
Very Short Answers | Q 57 | पृष्ठ १९८

संबंधित प्रश्‍न

Evaluate: `int sqrt(tanx)/(sinxcosx) dx`


Integrate the functions:

`(sin^(-1) x)/(sqrt(1-x^2))`


\[\int\sqrt{x - x^2} dx\]

\[\int\sqrt{9 - x^2}\text{ dx}\]

Write a value of

\[\int e^{\text{ log  sin x  }}\text{ cos x}. \text{ dx}\]

Write a value of\[\int\frac{1}{1 + 2 e^x} \text{ dx }\].


Write a value of\[\int\left( e^{x \log_e \text{  a}} + e^{a \log_e x} \right) dx\] .


Integrate the following w.r.t. x : x3 + x2 – x + 1


Integrate the following functions w.r.t. x : `(1 + x)/(x.sin (x + log x)`


Integrate the following functions w.r.t. x : `((x - 1)^2)/(x^2 + 1)^2`


Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`


Integrate the following functions w.r.t. x : `(4e^x - 25)/(2e^x - 5)`


Evaluate the following : `int (1)/sqrt(x^2 + 8x - 20).dx`


Evaluate the following integral:

`int (3cosx)/(4sin^2x + 4sinx - 1).dx`


Evaluate the following.

`int 1/("x" log "x")`dx


Evaluate the following.

`int x/(4x^4 - 20x^2 - 3) dx`


If f '(x) = `1/"x" + "x"` and f(1) = `5/2`, then f(x) = log x + `"x"^2/2` + ______


Fill in the Blank.

`int 1/"x"^3 [log "x"^"x"]^2 "dx" = "P" (log "x")^3` + c, then P = _______


If `int 1/(x + x^5)` dx = f(x) + c, then `int x^4/(x + x^5)`dx = ______


`int logx/x  "d"x`


`int cot^2x  "d"x`


`int sec^6 x tan x   "d"x` = ______.


`int(7x - 2)^2dx = (7x -2)^3/21 + c`


If `int(cosx - sinx)/sqrt(8 - sin2x)dx = asin^-1((sinx + cosx)/b) + c`. where c is a constant of integration, then the ordered pair (a, b) is equal to ______.


The integral `int ((1 - 1/sqrt(3))(cosx - sinx))/((1 + 2/sqrt(3) sin2x))dx` is equal to ______.


`int 1/(sinx.cos^2x)dx` = ______.


The value of `sqrt(2) int (sinx  dx)/(sin(x - π/4))` is ______.


`int x/sqrt(1 - 2x^4) dx` = ______.

(where c is a constant of integration)


Write `int cotx  dx`.


Evaluate.

`int(5"x"^2 - 6"x" + 3)/(2"x" - 3)  "dx"`


`int dx/((x+2)(x^2 + 1))`    ...(given)

`1/(x^2 +1) dx = tan ^-1 + c`


Prove that:

`int 1/sqrt(x^2 - a^2) dx = log |x + sqrt(x^2 - a^2)| + c`.


Evaluate:

`int(5x^2-6x+3)/(2x-3)dx`


Evaluate `int (1 + "x" + "x"^2/(2!))`dx


Evaluate `int(5x^2-6x+3)/(2x-3)dx`


Evaluate `int(1 + x + x^2 / (2!))dx`


Evaluate `int (5x^2 - 6x + 3)/(2x - 3) dx`


Evaluate the following.

`intx^3/sqrt(1 + x^4) dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×