मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Evaluate the following: ∫125-9x2⋅dx

Advertisements
Advertisements

प्रश्न

Evaluate the following:

`int (1)/(25 - 9x^2)*dx`

मूल्यांकन
Advertisements

उत्तर

I = `int (1)/(25 - 9x^2)*dx`

= `int(1)/(5^2 - (3x)^2)*dx`

= `(1)/(2(5))log |(5 + 3x)/(5 - 3x)|*(1)/(3) + c`

= `(1)/(30)log |(5 + 3x)/(5 - 3x)| + c`

Alternative Method:

`int (1)/(25 - 9x^2)*dx`

= `(1)/(9) int (1)/((25)/(9)x^2)*dx`

= `(1)/(9) int (1)/((5/3)^2 - x^2)*dx`

= `(1)/(9) xx (1)/(2 xx 5/3)log|(5/3 + x)/(5 / 3 - x)|+ c`

= `(1)/(30)log|(5 + 3x)/(5 - 3x)| + c`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.2 (B) [पृष्ठ १२३]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.2 (B) | Q 1.02 | पृष्ठ १२३

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Evaluate : `int(x-3)sqrt(x^2+3x-18)  dx`


Integrate the functions:

sin x ⋅ sin (cos x)


Integrate the functions:

`cos x /(sqrt(1+sinx))`


Integrate the functions:

`sqrt(tanx)/(sinxcos x)`


`(10x^9 + 10^x log_e 10)/(x^10 + 10^x)  dx` equals:


Solve:

dy/dx = cos(x + y)


Write a value of

\[\int \tan^6 x \sec^2 x \text{ dx }\] .

Write a value of

\[\int e^x \sec x \left( 1 + \tan x \right) \text{ dx }\]

Write a value of\[\int\frac{\sin x + \cos x}{\sqrt{1 + \sin 2x}} dx\]


Write a value of

\[\int\frac{a^x}{3 + a^x} \text{ dx}\]

Write a value of\[\int\frac{\sin x}{\cos^3 x} \text{ dx }\]


Write a value of\[\int\frac{1}{x \left( \log x \right)^n} \text { dx }\].


\[\text{ If } \int\left( \frac{x - 1}{x^2} \right) e^x dx = f\left( x \right) e^x + C, \text{ then  write  the value of  f}\left( x \right) .\]

\[\int\frac{\sin x + 2 \cos x}{2 \sin x + \cos x} \text{ dx }\]


Integrate the following w.r.t. x : `int x^2(1 - 2/x)^2 dx`


Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`


Integrate the following functions w.r.t. x : `(1)/(x.logx.log(logx)`.


Evaluate the following : `int (1)/sqrt(2x^2 - 5).dx`


Evaluate the following : `int sqrt((10 + x)/(10 - x)).dx`


Evaluate the following : `int (1)/sqrt(x^2 + 8x - 20).dx`


`int logx/(log ex)^2*dx` = ______.


Evaluate `int (1 + x + x^2/(2!))`dx


Evaluate `int (3"x"^2 - 5)^2` dx


Evaluate the following.

`int "x"^3/sqrt(1 + "x"^4)` dx


Evaluate the following.

`int "x"^5/("x"^2 + 1)`dx


Evaluate the following.

`int 1/(sqrt"x" + "x")` dx


Evaluate the following.

`int (2"e"^"x" + 5)/(2"e"^"x" + 1)`dx


Evaluate the following.

`int 1/(sqrt("x"^2 + 4"x"+ 29))` dx


Evaluate: `int (2"e"^"x" - 3)/(4"e"^"x" + 1)` dx


`int 1/(cos x - sin x)` dx = _______________


`int x/(x + 2)  "d"x`


`int x^3"e"^(x^2) "d"x`


`int[ tan (log x) + sec^2 (log x)] dx= ` ______


`int ("e"^x(x + 1))/(sin^2(x"e"^x)) "d"x` = ______.


`int (f^'(x))/(f(x))dx` = ______ + c.


`int(7x - 2)^2dx = (7x -2)^3/21 + c`


`int cos^3x  dx` = ______.


`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`


Evaluate `int(1+ x + x^2/(2!)) dx`


If f′(x) = 4x3 − 3x2 + 2x + k, f(0) = -1 and f(1) = 4, find f(x)


Evaluate `int 1/("x"("x" - 1)) "dx"`


Evaluate.

`int(5"x"^2 - 6"x" + 3)/(2"x" - 3)  "dx"`


Evaluate:

`int sin^2(x/2)dx`


Evaluate `int 1/(x(x-1))dx`


Evaluate `int(1+x+x^2/(2!))dx`


Evaluate the following.

`intx^3/sqrt(1 + x^4)dx`


After choosing \[u=g(x)\], what is the next step?


What must be done before integrating after obtaining \[du\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×