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प्रश्न
Integrate the following functions w.r.t. x : `3^(cos^2x) sin 2x`
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उत्तर
let I = `int 3^(cos^2x) sin2x dx`
Put cos2x = t
∴ `[2 cos x d/dx (cos x)]dx` = dt
∴ – 2 sin x cos x dx = dt
∴ sin 2x dx = – dt
I = `- int3^t dt`
= `-(1)/(log3).3^t + c`
= `-(1)/(log3).3^(cos^2x) + c`.
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