मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Evaluate the following: ∫1(x-3)(x+2).dx

Advertisements
Advertisements

प्रश्न

Evaluate the following:

`int (1)/sqrt((x - 3)(x + 2)).dx`

बेरीज
Advertisements

उत्तर

Let I = `int 1/sqrt((x - 3)(x + 2)).dx`

= `int 1/sqrt(x^2 - x - 6).dx`

= `int 1/sqrt((x^2 - x + 1/4) - 1/4 - 6).dx`

= `int 1/sqrt((x - 1/2)^2 - (5/2)^2).dx`

= `log|(x - 1/2) + sqrt((x - 1/2)^2 - (5/2)^2)| + c`

= `log|(x - 1/2) + sqrt(x^2 - x - 6)| + c`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.2 (B) [पृष्ठ १२३]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.2 (B) | Q 1.17 | पृष्ठ १२३

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Evaluate :`intxlogxdx`


Integrate the functions:

`sqrt(ax + b)`


Integrate the functions:

`(x^3 sin(tan^(-1) x^4))/(1 + x^8)`


`int (dx)/(sin^2 x cos^2 x)` equals:


\[\int\sqrt{3 + 2x - x^2} \text{ dx}\]

\[\int\cos x \sqrt{4 - \sin^2 x}\text{ dx}\]

Write a value of\[\int e^{ax} \sin\ bx\ dx\]


\[If \int e^x \left( \tan x + 1 \right)\text{ sec  x  dx } = e^x f\left( x \right) + C, \text{ then  write  the value  of  f}\left( x \right) .\]

 

 


The value of \[\int\frac{\cos \sqrt{x}}{\sqrt{x}} dx\] is


Evaluate the following integrals: `int(x - 2)/sqrt(x + 5).dx`


Integrate the following functions w.r.t. x : `(e^(2x) + 1)/(e^(2x) - 1)`


Integrate the following function w.r.t. x:

x9.sec2(x10)


Integrate the following functions w.r.t.x:

`(2sinx cosx)/(3cos^2x + 4sin^2 x)`


Evaluate the following : `int (1)/(7 + 2x^2).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2sinx).dx`


Integrate the following functions w.r.t. x : `int (1)/(cosx - sinx).dx`


Evaluate the following integrals :  `int (3x + 4)/sqrt(2x^2 + 2x + 1).dx`


Evaluate the following integrals:

`int (7x + 3)/sqrt(3 + 2x - x^2).dx`


Evaluate `int 1/(x (x - 1))` dx


If f'(x) = x2 + 5 and f(0) = −1, then find the value of f(x).


Evaluate the following.

`int 1/("x" log "x")`dx


Evaluate the following.

`int (2"e"^"x" + 5)/(2"e"^"x" + 1)`dx


Evaluate the following.

`int 1/(4x^2 - 20x + 17)` dx


Evaluate the following.

`int x/(4x^4 - 20x^2 - 3) dx`


Evaluate the following.

`int 1/("a"^2 - "b"^2 "x"^2)` dx


`int ("x + 2")/(2"x"^2 + 6"x" + 5)"dx" = "p" int (4"x" + 6)/(2"x"^2 + 6"x" + 5) "dx" + 1/2 int "dx"/(2"x"^2 + 6"x" + 5)`, then p = ?


`int (x^2 + x - 6)/((x - 2)(x - 1))dx = x` + ______ + c


Evaluate `int 1/((2"x" + 3))` dx


Evaluate: `int "e"^"x" (1 + "x")/(2 + "x")^2` dx


`int ("e"^(3x))/("e"^(3x) + 1)  "d"x`


`int sqrt(x)  sec(x)^(3/2) tan(x)^(3/2)"d"x`


State whether the following statement is True or False:

`int sqrt(1 + x^2) *x  "d"x = 1/3(1 + x^2)^(3/2) + "c"`


`int[ tan (log x) + sec^2 (log x)] dx= ` ______


if `f(x) = 4x^3 - 3x^2 + 2x +k, f (0) = - 1 and f (1) = 4, "find " f(x)`


If f′(x) = 4x3 − 3x2 + 2x + k, f(0) = -1 and f(1) = 4, find f(x)


Evaluate:

`int 1/(1 + cosα . cosx)dx`


Evaluate `int (1)/(x(x - 1))dx`


Evaluate:

`int sqrt((a - x)/x) dx`


Evaluate the following.

`intxsqrt(1+x^2)dx`


Evaluate `int (1 + x + x^2/(2!)) dx`


Evaluate:

`int(5x^2-6x+3)/(2x-3)dx`


Evaluate `int(1+x+x^2/(2!))dx`


Evaluate `int (1 + "x" + "x"^2/(2!))`dx


Evaluate `int(5x^2-6x+3)/(2x-3) dx`


Evaluate `int (1 + x + x^2/(2!)) dx`


Evaluate the following:

`int x^3/(sqrt(1 + x^4)) dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate `int 1/(x(x-1)) dx`


`int (x + 1)/(x(1 + xe^x)) dx` is equal to


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×