मराठी

Integrate the functions: x3sin(tan-1x4)1+x8 - Mathematics

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प्रश्न

Integrate the functions:

`(x^3 sin(tan^(-1) x^4))/(1 + x^8)`

बेरीज
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उत्तर

Let `I = int (x^3 sin (tan^-1 x^4))/(1 + x^8)` dx

Put tan-1 x4 = t 

or `1/(1 + x^8) * 4x^3 dx = dt`

`1/(1 + x^8). x^3 = 1/4 dt`

Hence, `I = 1/4 int sin t dt`

`= - 1/4  cos t + C`

`= - 1/4 cos (tan^-1 x^4) + C`

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पाठ 7: Integrals - Exercise 7.2 [पृष्ठ ३०५]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.2 | Q 37 | पृष्ठ ३०५

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