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प्रश्न
Evaluate the following integrals:
`int (cos2x)/sin^2x dx`
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उत्तर
`int (cos2x)/sin^2x dx`
= `int((1 - 2sin^2x))/sin^2x dx`
= `int(1/sin^2x - (2sin^2x)/sin^2x)dx`
= `int "cosec"^2x dx - 2 int dx`
= – cot x – 2x + c.
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