मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Integrate the following functions w.r.t. x : sin(x-a)cos(x +b)

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t. x : `sin(x - a)/cos(x  + b)`

बेरीज
Advertisements

उत्तर

Let I = `intsin(x - a)/cos(x + b).dx`

= `int(sin[(x + b) - (a  + b)])/cos(x + b).dx`

= `int[sin(x + b) cos(a + b) - cos(x + b)sin(a + b))/cos(x + b).dx`

= `int[(sin(x + b) cos(a + b))/cos(x + b) - (cos(x + b)sin(a + b))/cos(x + b)].dx`

= `cos (a + b) int tan (x + b) dx - sin (a + b) int 1dx`

= cos (a + b) log | sec (x + b) | – x sin (a + b) + c.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.2 (A) [पृष्ठ ११०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.2 (A) | Q 2.03 | पृष्ठ ११०

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Integrate the functions:

sin x ⋅ sin (cos x)


Integrate the functions:

`e^(2x+3)`


Integrate the functions:

`(2cosx - 3sinx)/(6cos x + 4 sin x)`


Integrate the functions:

`cos x /(sqrt(1+sinx))`


\[\int\sqrt{9 - x^2}\text{ dx}\]

Write a value of

\[\int \tan^6 x \sec^2 x \text{ dx }\] .

Write a value of

\[\int\frac{\cos x}{3 + 2 \sin x}\text{  dx}\]

Write a value of

\[\int e^x \sec x \left( 1 + \tan x \right) \text{ dx }\]

Write a value of

\[\int e^{\text{ log  sin x  }}\text{ cos x}. \text{ dx}\]

Write a value of \[\int\frac{1 - \sin x}{\cos^2 x} \text{ dx }\]


Integrate the following w.r.t. x:

`2x^3 - 5x + 3/x + 4/x^5`


Evaluate the following integrals:

`int (cos2x)/sin^2x dx` 


Evaluate the following integrals : `int cos^2x.dx`


Integrate the following functions w.r.t. x : `sqrt(tanx)/(sinx.cosx)`


Integrate the following functions w.r.t. x : `((x - 1)^2)/(x^2 + 1)^2`


Integrate the following functions w.r.t. x:

`x^5sqrt(a^2 + x^2)`


Integrate the following functions w.r.t.x:

cos8xcotx


Evaluate the following:

`int (1)/(25 - 9x^2)*dx`


Evaluate the following : `int  (1)/(x^2 + 8x + 12).dx`


Integrate the following functions w.r.t. x : `int (1)/(4 - 5cosx).dx`


Evaluate the following integrals : `int sqrt((9 - x)/x).dx`


`int logx/(log ex)^2*dx` = ______.


Evaluate `int 1/(x (x - 1))` dx


Evaluate the following.

`int ("2x" + 6)/(sqrt("x"^2 + 6"x" + 3))` dx


Evaluate the following.

`int 1/(7 + 6"x" - "x"^2)` dx


Evaluate the following.

`int 1/(sqrt("x"^2 -8"x" - 20))` dx


Choose the correct alternative from the following.

The value of `int "dx"/sqrt"1 - x"` is


`int (x^2 + x - 6)/((x - 2)(x - 1))dx = x` + ______ + c


Evaluate: If f '(x) = `sqrt"x"` and f(1) = 2, then find the value of f(x).


Evaluate: `int log ("x"^2 + "x")` dx


Evaluate: `int sqrt("x"^2 + 2"x" + 5)` dx


`int 1/sqrt((x - 3)(x + 2))` dx = ______.


`int (2 + cot x - "cosec"^2x) "e"^x  "d"x`


`int cot^2x  "d"x`


General solution of `(x + y)^2 ("d"y)/("d"x) = "a"^2, "a" ≠ 0` is ______. (c is arbitrary constant)


`int[ tan (log x) + sec^2 (log x)] dx= ` ______


`int ("e"^x(x + 1))/(sin^2(x"e"^x)) "d"x` = ______.


`int 1/(a^2 - x^2) dx = 1/(2a) xx` ______.


`int secx/(secx - tanx)dx` equals ______.


if `f(x) = 4x^3 - 3x^2 + 2x +k, f (0) = - 1 and f (1) = 4, "find " f(x)`


If f′(x) = 4x3 − 3x2 + 2x + k, f(0) = -1 and f(1) = 4, find f(x)


Evaluate `int 1/("x"("x" - 1)) "dx"`


Evaluate the following.

`int x sqrt(1 + x^2)  dx`


Evaluate the following.

`int1/(x^2+4x-5) dx`


Evaluate the following

`int x^3 e^(x^2) ` dx


Evaluate `int1/(x(x - 1))dx`


Evaluate `int 1/(x(x-1)) dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×