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प्रश्न
Integrate the functions:
sec2(7 – 4x)
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उत्तर
Let `I = int sec^2` (7 - 4x) dx
Put 7 - 4x = t
- 4 dx = dt or dx `= - 1/4` dt
Hence, `I = - 1/4 int sec^2` t dt
`= - 1/4` tan t + C
`= - 1/4` tan (7 - 4x) + C
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