मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

To find the value of ∫(1+logx)x dx the proper substitution is ______

Advertisements
Advertisements

प्रश्न

To find the value of `int ((1 + logx))/x` dx the proper substitution is ______

रिकाम्या जागा भरा
Advertisements

उत्तर

1 + log x = t

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1.5: Integration - Q.2

संबंधित प्रश्‍न

Evaluate :   `∫1/(cos^4x+sin^4x)dx`


Integrate the functions:

`(log x)^2/x`


Integrate the functions:

`(x^3 - 1)^(1/3) x^5`


Integrate the functions:

`(sin x)/(1+ cos x)^2`


Evaluate: `int (2y^2)/(y^2 + 4)dx`


Write a value of

\[\int\frac{\cos x}{3 + 2 \sin x}\text{  dx}\]

Write a value of\[\int e^{ax} \sin\ bx\ dx\]


Write a value of\[\int e^{ax} \cos\ bx\ dx\].

 


Evaluate the following integrals:

tan2x dx


Integrate the following functions w.r.t. x : `e^(3x)/(e^(3x) + 1)`


Integrate the following functions w.r.t. x : sin4x.cos3x


Integrate the following functions w.r.t. x : `((x - 1)^2)/(x^2 + 1)^2`


Integrate the following functions w.r.t. x : cos7x


Evaluate the following integrals:

`int (2x + 1)/(x^2 + 4x - 5).dx`


Fill in the Blank.

`int 1/"x"^3 [log "x"^"x"]^2 "dx" = "P" (log "x")^3` + c, then P = _______


`int (2(cos^2 x - sin^2 x))/(cos^2 x + sin^2 x)` dx = ______________


If `int 1/(x + x^5)` dx = f(x) + c, then `int x^4/(x + x^5)`dx = ______


`int cot^2x  "d"x`


`int (f^'(x))/(f(x))dx` = ______ + c.


`int x/sqrt(1 - 2x^4) dx` = ______.

(where c is a constant of integration)


Evaluate `int(1+ x + x^2/(2!)) dx`


Evaluate `int1/(x(x-1))dx`


If f '(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate the following.

`int1/(x^2 + 4x - 5)  dx`


Evaluate `int 1/(x(x-1))dx`


Evaluate the following.

`intx^3/sqrt(1 + x^4)dx`


Evaluate the following.

`intx^3/sqrt(1 + x^4) dx`


`int (x + 1)/(x(1 + xe^x)) dx` is equal to


If \[x=g(t)\] and \[dx=g'(t)dt\], which formula represents integration by substitution?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×