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Integrate the functions: sec2(7 – 4x)

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Question

Integrate the functions:

sec2(7 – 4x)

Sum
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Solution

Let `I = int sec^2` (7 - 4x) dx

Put 7 - 4x = t

- 4 dx = dt or dx `= - 1/4` dt

Hence, `I = - 1/4 int sec^2` t dt

`= - 1/4` tan t + C

`= - 1/4` tan (7 - 4x) + C

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Chapter 7: Integrals - Exercise 7.2 [Page 305]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.2 | Q 22 | Page 305

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