Advertisements
Advertisements
प्रश्न
`int ("x + 2")/(2"x"^2 + 6"x" + 5)"dx" = "p" int (4"x" + 6)/(2"x"^2 + 6"x" + 5) "dx" + 1/2 int "dx"/(2"x"^2 + 6"x" + 5)`, then p = ?
पर्याय
`1/3`
`1/2`
`1/4`
2
Advertisements
उत्तर
`1/4`
Explanation:
Let x + 2 = p `"d"/"dx" (2"x"^2 + 6"x" + 5) + "q"`
= p(4x + 6) + q
∴ x + 2 = 4px + 6p + q
∴ 4p = 1 and 6p + q = 2
∴ p = `1/4`
APPEARS IN
संबंधित प्रश्न
Evaluate :
`int(sqrt(cotx)+sqrt(tanx))dx`
Find: `int(x+3)sqrt(3-4x-x^2dx)`
Integrate the functions:
`(x^3 - 1)^(1/3) x^5`
Integrate the functions:
`(e^(2x) - 1)/(e^(2x) + 1)`
Integrate the functions:
`cos sqrt(x)/sqrtx`
Evaluate: `int (2y^2)/(y^2 + 4)dx`
Write a value of
`int "dx"/(9"x"^2 + 1)= ______. `
Evaluate the following integrals : tan2x dx
If `f'(x) = x - (3)/x^3, f(1) = (11)/(2)`, find f(x)
Integrate the following functions w.r.t. x : `sin(x - a)/cos(x + b)`
Evaluate the following : `int (1)/(7 + 2x^2).dx`
Evaluate the following : `int sqrt((9 + x)/(9 - x)).dx`
Evaluate the following : `int (1)/(x^2 + 8x + 12).dx`
Evaluate the following : `int (1)/sqrt(3x^2 + 5x + 7).dx`
Integrate the following functions w.r.t. x : `int (1)/(cosx - sqrt(3)sinx).dx`
Choose the correct options from the given alternatives :
`int (e^(2x) + e^-2x)/e^x*dx` =
State whether the following statement is True or False.
The proper substitution for `int x(x^x)^x (2log x + 1) "d"x` is `(x^x)^x` = t
`int (2 + cot x - "cosec"^2x) "e"^x "d"x`
`int ("e"^(2x) + "e"^(-2x))/("e"^x) "d"x`
`int "dx"/((sin x + cos x)(2 cos x + sin x))` = ?
`int sqrt(x^2 - a^2)/x dx` = ______.
`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`
Evaluate the following.
`int(20 - 12"e"^"x")/(3"e"^"x" - 4) "dx"`
Evaluate `int 1/(x(x-1))dx`
`int x^2/sqrt(1 - x^6)dx` = ______.
Evaluate the following.
`intx sqrt(1 +x^2) dx`
Evaluate the following:
`int x^3/(sqrt(1+x^4))dx`
