Advertisements
Advertisements
प्रश्न
`int ("x + 2")/(2"x"^2 + 6"x" + 5)"dx" = "p" int (4"x" + 6)/(2"x"^2 + 6"x" + 5) "dx" + 1/2 int "dx"/(2"x"^2 + 6"x" + 5)`, then p = ?
विकल्प
`1/3`
`1/2`
`1/4`
2
Advertisements
उत्तर
`1/4`
Explanation:
Let x + 2 = p `"d"/"dx" (2"x"^2 + 6"x" + 5) + "q"`
= p(4x + 6) + q
∴ x + 2 = 4px + 6p + q
∴ 4p = 1 and 6p + q = 2
∴ p = `1/4`
APPEARS IN
संबंधित प्रश्न
Find the particular solution of the differential equation x2dy = (2xy + y2) dx, given that y = 1 when x = 1.
Integrate the functions:
`x^2/(2+ 3x^3)^3`
Write a value of
Write a value of\[\int\frac{\sin x + \cos x}{\sqrt{1 + \sin 2x}} dx\]
Evaluate: \[\int\frac{x^3 - 1}{x^2} \text{ dx}\]
Evaluate the following integral:
`int(4x + 3)/(2x + 1).dx`
Integrate the following functions w.r.t. x : `(x^2 + 2)/((x^2 + 1)).a^(x + tan^-1x)`
Integrate the following functions w.r.t. x : e3logx(x4 + 1)–1
Integrate the following functions w.r.t. x : cos7x
Integrate the following functions w.r.t. x : sin5x.cos8x
Integrate the following functions w.r.t. x : `int (1)/(2sin 2x - 3)dx`
Evaluate the following integrals:
`int (2x + 1)/(x^2 + 4x - 5).dx`
Evaluate the following.
`int (1 + "x")/("x" + "e"^"-x")` dx
Evaluate the following.
`int 1/(sqrt"x" + "x")` dx
Evaluate the following.
`int 1/(7 + 6"x" - "x"^2)` dx
Evaluate `int (5"x" + 1)^(4/9)` dx
`int x^2/sqrt(1 - x^6)` dx = ________________
`int x^x (1 + logx) "d"x`
`int (f^'(x))/(f(x))dx` = ______ + c.
The value of `intsinx/(sinx - cosx)dx` equals ______.
Write `int cotx dx`.
Solve the following Evaluate.
`int(5x^2 - 6x + 3)/(2x - 3)dx`
Evaluate:
`int(cos 2x)/sinx dx`
Evaluate:
`intsqrt(3 + 4x - 4x^2) dx`
Evaluate `int (1 + "x" + "x"^2/(2!))`dx
If f'(x) = 4x3 – 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).
