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Write a Value of ∫ Cos X 3 + 2 Sin X D X - Mathematics

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प्रश्न

Write a value of

\[\int\frac{\cos x}{3 + 2 \sin x}\text{  dx}\]
योग
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उत्तर

\[\text{ Let I} = \int \frac{\cos x}{3 + 2 \sin x}dx\]
\[\text{ Let 3} + 2 \sin x = t\]
\[ \Rightarrow 2 \text{ cos x dx }= dt\]
\[ \Rightarrow \text{ cos x dx }= \frac{dt}{2}\]
\[ \therefore I = \frac{1}{2}\int\frac{dt}{t}\]
\[ = \int\frac{1}{2} \text{ log }\left| t \right| + C\]
\[ = \frac{1}{2}\text{ log} \left| 3 + 2 \sin x \right| + C \left( \because t = 3 + 2 \text{ sin x} \right)\]

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अध्याय 19: Indefinite Integrals - Very Short Answers [पृष्ठ १९७]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Very Short Answers | Q 7 | पृष्ठ १९७

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