Advertisements
Advertisements
प्रश्न
Write a value of
Advertisements
उत्तर
Let I= \[\int\] tan6 x . sec2 x dx
sec2 x dx = dt
\[= \frac{t^7}{7} + C\]
\[ = \frac{\tan^7 x}{7} + C \left( \because t = \tan x \right)\]
APPEARS IN
संबंधित प्रश्न
Evaluate : `∫1/(cos^4x+sin^4x)dx`
Integrate the functions:
`1/(cos^2 x(1-tan x)^2`
Integrate the functions:
`cos sqrt(x)/sqrtx`
Evaluate: `int 1/(x(x-1)) dx`
Write a value of\[\int \cos^4 x \text{ sin x dx }\]
Write a value of\[\int a^x e^x \text{ dx }\]
Write a value of\[\int\sqrt{9 + x^2} \text{ dx }\].
Integrate the following w.r.t. x : x3 + x2 – x + 1
Integrate the following w.r.t. x:
`3 sec^2x - 4/x + 1/(xsqrt(x)) - 7`
Evaluate the following integrals : `int (sin2x)/(cosx)dx`
Evaluate the following integrals:
`int (cos2x)/sin^2x dx`
Evaluate the following : `int (1)/(4 + 3cos^2x).dx`
Evaluate the following integrals : `int sqrt((x - 7)/(x - 9)).dx`
Choose the correct options from the given alternatives :
`int (e^(2x) + e^-2x)/e^x*dx` =
Evaluate `int (3"x"^2 - 5)^2` dx
Fill in the Blank.
`int (5("x"^6 + 1))/("x"^2 + 1)` dx = x4 + ______ x3 + 5x + c
To find the value of `int ((1 + log x) )/x dx` the proper substitution is ______.
Evaluate `int (5"x" + 1)^(4/9)` dx
Evaluate `int "x - 1"/sqrt("x + 4")` dx
`int e^x/x [x (log x)^2 + 2 log x]` dx = ______________
`int 1/(xsin^2(logx)) "d"x`
`int (cos2x)/(sin^2x) "d"x`
`int x/(x + 2) "d"x`
`int x^3"e"^(x^2) "d"x`
`int (f^'(x))/(f(x))dx` = ______ + c.
If `int(cosx - sinx)/sqrt(8 - sin2x)dx = asin^-1((sinx + cosx)/b) + c`. where c is a constant of integration, then the ordered pair (a, b) is equal to ______.
Write `int cotx dx`.
Evaluate `int(1+ x + x^2/(2!)) dx`
Solve the following Evaluate.
`int(5x^2 - 6x + 3)/(2x - 3)dx`
`int x^3 e^(x^2) dx`
Evaluate:
`int 1/(1 + cosα . cosx)dx`
Evaluate the following.
`int x^3 e^(x^2) dx`
Evaluate.
`int (5x^2 -6x + 3)/(2x -3)dx`
Evaluate `int1/(x(x-1))dx`
If f '(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).
Evaluate the following.
`int 1/ (x^2 + 4x - 5) dx`
Evaluate `int(5x^2-6x+3)/(2x-3)dx`
If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).
