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∫1xsin2(logx) dx

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प्रश्न

`int 1/(xsin^2(logx))  "d"x`

योग
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उत्तर

Let I = `int 1/(x*sin^2(logx))  "d"x`

Put log x = t

∴ `1/x  "d"x` = dt

∴ I = `int 1/(sin^2"t")  "dt"`

= `int "cosec"^2"t"*"dt"`

= − cot t + c

∴ I = − cot (log x) + c 

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अध्याय 2.3: Indefinite Integration - Very Short Answers

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