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int sqrt(1 + sin2x) dx

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प्रश्न

`int sqrt(1 + sin2x)  dx`

Evaluate: `int sqrt(1 + sin 2x)  dx`

मूल्यांकन
योग
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उत्तर

`int sqrt(1 + sin2x)  dx`

= `int sqrt(sin^2x + cos^2x + 2 sinx cosx)  dx`

= `int sqrt((cosx + sinx)^2) dx`

= `int (cosx + sinx) dx`

= sin x – cos x + c

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अध्याय 2.3: Indefinite Integration - Very Short Answers

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