हिंदी

Integrate the following w.r.t. x: 3sec2x-4x+1xx-7 - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Integrate the following w.r.t. x:

`3 sec^2x - 4/x + 1/(xsqrt(x)) - 7`

योग
Advertisements

उत्तर

`int (3 sec^2 x - 4/x + 1/(xsqrt(x)) - 7)dx`

= `3int sec^2x  dx - 4 int 1/x dx +  intx ^(-(3)/(2)) dx - 7 int 1 dx`

= `3 tan x - 4 log |x| + (x ^(- 3/2 + 1))/(-3/2 + 1) - 7x + c`

= `3 tan x - 4 log |x| + (x ^(- 1/2 ))/(-1/2) - 7x + c`

= `3 tan x - 4 log |x| + (-2x^(-1/2)) - 7x + c`

= `3tan x - 4 log |x| - 2/sqrt(x) - 7x + c`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.1 [पृष्ठ १०२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.1 | Q 1.3 | पृष्ठ १०२

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Evaluate : `int (sinx)/sqrt(36-cos^2x)dx`


Find `intsqrtx/sqrt(a^3-x^3)dx`


Integrate the functions:

`1/(x(log x)^m),  x > 0, m ne 1`


Integrate the functions:

`(2cosx - 3sinx)/(6cos x + 4 sin x)`


Integrate the functions:

`sin x/(1+ cos x)`


Evaluate: `int 1/(x(x-1)) dx`


\[\int\sqrt{x^2 + x + 1} \text{ dx}\]

Write a value of

\[\int \tan^3 x \sec^2 x \text{ dx }\].

 


Write a value of

\[\int\frac{\cos x}{3 + 2 \sin x}\text{  dx}\]

Write a value of\[\int\frac{1}{1 + 2 e^x} \text{ dx }\].


Write a value of\[\int\left( e^{x \log_e \text{  a}} + e^{a \log_e x} \right) dx\] .


Write a value of\[\int\sqrt{x^2 - 9} \text{ dx}\]


Integrate the following functions w.r.t. x : `(e^(2x) + 1)/(e^(2x) - 1)`


Integrate the following functions w.r.t. x : `(1)/(4x + 5x^-11)`


Integrate the following function w.r.t. x:

`(10x^9 +10^x.log10)/(10^x + x^10)`


Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`


Integrate the following functions w.r.t. x : `cosx/sin(x - a)`


Integrate the following functions w.r.t.x:

cos8xcotx


Evaluate the following : `int (1)/sqrt(2x^2 - 5).dx`


Choose the correct options from the given alternatives : 

`int dx/(cosxsqrt(sin^2x - cos^2x))*dx` =


Choose the correct options from the given alternatives :

`int (cos2x - 1)/(cos2x + 1)*dx` =


If f'(x) = 4x3 − 3x2  + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate the following.

`int 1/(sqrt"x" + "x")` dx


Evaluate the following.

`int "x"^3/(16"x"^8 - 25)` dx


Evaluate the following.

`int 1/(sqrt("x"^2 + 4"x"+ 29))` dx


Choose the correct alternative from the following.

The value of `int "dx"/sqrt"1 - x"` is


Evaluate: `int 1/(2"x" + 3"x" log"x")` dx


`int 1/sqrt((x - 3)(x + 2))` dx = ______.


`int sqrt(1 + sin2x)  dx`


`int "e"^x[((x + 3))/((x + 4)^2)] "d"x`


State whether the following statement is True or False:

`int"e"^(4x - 7)  "d"x = ("e"^(4x - 7))/(-7) + "c"`


`int sin^-1 x`dx = ?


If f(x) = 3x + 6, g(x) = 4x + k and fog (x) = gof (x) then k = ______.


`int ("d"x)/(x(x^4 + 1))` = ______.


`int 1/(a^2 - x^2) dx = 1/(2a) xx` ______.


`int(3x + 1)/(2x^2 - 2x + 3)dx` equals ______.


`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`


Find `int dx/sqrt(sin^3x cos(x - α))`.


Evaluate the following.

`int x sqrt(1 + x^2)  dx`


Evaluate the following.

`int(1)/(x^2 + 4x - 5)dx`


`int "cosec"^4x  dx` = ______.


`int 1/(sin^2x cos^2x)dx` = ______.


Evaluate:

`int sin^3x cos^3x  dx`


Evaluate the following.

`int "x"^3/sqrt(1 + "x"^4)` dx


Evaluate `int(5x^2-6x+3)/(2x-3) dx`


Evaluate `int1/(x(x - 1))dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×