हिंदी

Choose the correct options from the given alternatives : ∫dxcosxsin2x-cos2x⋅dx =

Advertisements
Advertisements

प्रश्न

Choose the correct options from the given alternatives : 

`int dx/(cosxsqrt(sin^2x - cos^2x))*dx` =

विकल्प

  • `log(tanx - sqrt(tan^2x - 1)) + c`

  • sin–1 (tan x) + c

  • 1 + sin–1 (cot x) + c

  • `log(tanx + sqrt(tan^2x - 1)) + c`

MCQ
Advertisements

उत्तर

`log(tanx + sqrt(tan^2x - 1)) + c`

[ Hint : `int dx/(cosxsqrt(sin^2x - cos^2x)`

= `int (sec2x*dx)/sqrt(tan2x - 1)`     ...[Dividing by cos2x]
Put tan x = t].

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Miscellaneous Exercise 3 [पृष्ठ १४९]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.16 | पृष्ठ १४९

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Evaluate: `int sqrt(tanx)/(sinxcosx) dx`


Integrate the functions:

`(log x)^2/x`


Integrate the functions:

`1/(x + x log x)`


Integrate the functions:

sin (ax + b) cos (ax + b)


Integrate the functions:

`sqrt(ax + b)`


Integrate the functions:

`x^2/(2+ 3x^3)^3`


Integrate the functions:

`(x^3 sin(tan^(-1) x^4))/(1 + x^8)`


`(10x^9 + 10^x log_e 10)/(x^10 + 10^x)  dx` equals:


Evaluate: `int_0^3 f(x)dx` where f(x) = `{(cos 2x, 0<= x <= pi/2),(3, pi/2 <= x <= 3) :}`


\[\int\sqrt{16 x^2 + 25} \text{ dx}\]

Write a value of\[\int e^x \left( \frac{1}{x} - \frac{1}{x^2} \right) dx\] .


Write a value of\[\int\sqrt{4 - x^2} \text{ dx }\]


 Show that : `int _0^(pi/4) "log" (1+"tan""x")"dx" = pi /8 "log"2`


Integrate the following w.r.t. x : `int x^2(1 - 2/x)^2 dx`


Evaluate the following integrals : `int tanx/(sec x + tan x)dx`


Evaluate the following integrals:

`int x/(x + 2).dx`


Evaluate the following integrals: `int (2x - 7)/sqrt(4x - 1).dx`


Evaluate the following integrals : `int cos^2x.dx`


Evaluate the following integrals:

`int(2)/(sqrt(x) - sqrt(x + 3)).dx`


Integrate the following functions w.r.t. x : `sqrt(tanx)/(sinx.cosx)`


Integrate the following functions w.r.t. x : `sin(x - a)/cos(x  + b)`


Evaluate the following : `int (1)/sqrt(11 - 4x^2).dx`


Evaluate the following : `int sqrt((2 + x)/(2 - x)).dx`


Evaluate the following : `(1)/(4x^2 - 20x + 17)`


Evaluate the following : `int (logx)2.dx`


Evaluate the following.

`int 1/(4"x"^2 - 1)` dx


Evaluate the following.

`int 1/(sqrt(3"x"^2 - 5))` dx


State whether the following statement is True or False.

If ∫ x f(x) dx = `("f"("x"))/2`, then find f(x) = `"e"^("x"^2)`


If `int 1/(x + x^5)` dx = f(x) + c, then `int x^4/(x + x^5)`dx = ______


`int cot^2x  "d"x`


`int x/(x + 2)  "d"x`


`int(5x + 2)/(3x - 4) dx` = ______


`int "e"^(sin^-1 x) ((x + sqrt(1 - x^2))/(sqrt1 - x^2)) "dx" = ?`


`int sec^6 x tan x   "d"x` = ______.


The value of `intsinx/(sinx - cosx)dx` equals ______.


`int 1/(sinx.cos^2x)dx` = ______.


The value of `sqrt(2) int (sinx  dx)/(sin(x - π/4))` is ______.


Evaluate `int_-a^a f(x) dx`, where f(x) = `9^x/(1 + 9^x)`.


Evaluate the following

`int1/(x^2 +4x-5)dx`


Evaluate the following.

`int 1/(x^2 + 4x - 5)  dx`


Evaluate.

`int (5x^2 - 6x + 3)/(2x - 3) dx`


Evaluate:

`int sqrt((a - x)/x) dx`


Evaluate the following.

`int(1)/(x^2 + 4x - 5)dx`


Evaluate the following.

`intxsqrt(1+x^2)dx`


If f '(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


`int (x + 1)/(x(1 + xe^x)) dx` is equal to


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×