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प्रश्न
Integrate the functions:
`(log x)^2/x`
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उत्तर
Let `I = int (log x)^2/x` dx
Put log x = t
`1/x` dx = dt
Hence, `I = int t^2` dt
`I = t^3/3 + C`
`I = 1/3 (log x)^3 + C`
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