हिंदी

Integrate the following functions w.r.t. x : sin5x.cos8x - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Integrate the following functions w.r.t. x : sin5x.cos8x

योग
Advertisements

उत्तर

Let I = `int sin^5xcos^8xdx`

=`int sin^4xcos^8xsinxdx`

= `int(1 - cos^2x)^2 cos^8xsinxdx`
Put cos x = t
∴ – sin x dx = dt
∴ sin x dx = – dt
I = `- int(1 - t^2)^2t^8 dt`

= `- int(1 - 2t^2 + t^4)t^8 dt`

= `- int (t^8 - 2t^10 + t^12)dt`

= `- int t^8dt + 2 intt^10 dt - int t^12 dt`

= `- t^9/(9) + 2(t^11/11) - t^13/(13) + c`

= `-(1)/(9)cos^9x + (2)/(11)cos^11x - (1)/(13)cos^13x + c`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.2 (A) [पृष्ठ ११०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.2 (A) | Q 2.14 | पृष्ठ ११०

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Evaluate :   `∫1/(cos^4x+sin^4x)dx`


 
 

Evaluate :

`int1/(sin^4x+sin^2xcos^2x+cos^4x)dx`

 
 

Integrate the functions:

`1/(x + x log x)`


`int (dx)/(sin^2 x cos^2 x)` equals:


\[\int\sqrt{3 + 2x - x^2} \text{ dx}\]

Write a value of

\[\int\frac{1 + \cot x}{x + \log \sin x} \text{ dx }\]

Write a value of

\[\int \tan^6 x \sec^2 x \text{ dx }\] .

Write a value of\[\int\frac{\sin x - \cos x}{\sqrt{1 + \sin 2x}} \text{ dx}\]


Write a value of\[\int\sqrt{x^2 - 9} \text{ dx}\]


Evaluate:  \[\int\frac{x^3 - 1}{x^2} \text{ dx}\]


\[\int\frac{\sin x + 2 \cos x}{2 \sin x + \cos x} \text{ dx }\]


 Show that : `int _0^(pi/4) "log" (1+"tan""x")"dx" = pi /8 "log"2`


Integrate the following w.r.t. x:

`2x^3 - 5x + 3/x + 4/x^5`


Evaluate the following integrals : `int tanx/(sec x + tan x)dx`


Evaluate the following integrals:

`int(2)/(sqrt(x) - sqrt(x + 3)).dx`


Integrate the following function w.r.t. x:

`(10x^9 +10^x.log10)/(10^x + x^10)`


Integrate the following functions w.r.t. x : `sin(x - a)/cos(x  + b)`


Evaluate the following : `int (1)/sqrt(11 - 4x^2).dx`


Evaluate the following integrals :  `int (3x + 4)/sqrt(2x^2 + 2x + 1).dx`


Evaluate the following.

`int ((3"e")^"2t" + 5)/(4"e"^"2t" - 5)`dt


Evaluate: `int (2"e"^"x" - 3)/(4"e"^"x" + 1)` dx


Evaluate: `int log ("x"^2 + "x")` dx


Evaluate: `int sqrt(x^2 - 8x + 7)` dx


`int sqrt(x^2 + 2x + 5)` dx = ______________


`int cot^2x  "d"x`


`int "dx"/((sin x + cos x)(2 cos x + sin x))` = ?


If `tan^-1x = 2tan^-1((1 - x)/(1 + x))`, then the value of x is ______ 


If I = `int (sin2x)/(3x + 4cosx)^3 "d"x`, then I is equal to ______.


`int(sin2x)/(5sin^2x+3cos^2x)  dx=` ______.


If f'(x) = `x + 1/x`, then f(x) is ______.


`int 1/(a^2 - x^2) dx = 1/(2a) xx` ______.


`int (sin  (5x)/2)/(sin  x/2)dx` is equal to ______. (where C is a constant of integration).


`int(log(logx) + 1/(logx)^2)dx` = ______.


The value of `int (sinx + cosx)/sqrt(1 - sin2x) dx` is equal to ______.


`int (x + sinx)/(1 + cosx)dx` is equal to ______.


Write `int cotx  dx`.


Find `int dx/sqrt(sin^3x cos(x - α))`.


Evaluated the following

`int x^3/ sqrt (1 + x^4 )dx`


Evaluate the following

`int x^3/sqrt(1+x^4) dx`


If f'(x) = 4x3- 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate:

`intsqrt(3 + 4x - 4x^2)  dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)dx`


Evaluate the following.

`int "x"^3/sqrt(1 + "x"^4)` dx


Evaluate the following.

`int 1/ (x^2 + 4x - 5) dx`


Evaluate `int(5x^2-6x+3)/(2x-3)dx`


Evaluate `int (1 + x + x^2/(2!)) dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate:

`intsqrt(sec  x/2 - 1)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×