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Choose the correct options from the given alternatives : ∫cos2x-1cos2x+1⋅dx =

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प्रश्न

Choose the correct options from the given alternatives :

`int (cos2x - 1)/(cos2x + 1)*dx` =

विकल्प

  • tan x – x + c

  • x + tan x + c

  • x – tan x + c

  • – x – cot x + c

MCQ
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उत्तर

x – tan x + c

[ Hint : `int (cos2x - 1)/(cos2x + 1)*dx`

= `int (-(1 - cos2x))/(1 + cos^2x)*dx`

= `int (-2sin^2x)/(2cos^2x)*dx`

= `int (sec^2x - 1)*dx`

= – tan x + x + c.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Miscellaneous Exercise 3 [पृष्ठ १५०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.19 | पृष्ठ १५०

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