हिंदी

Choose the correct options from the given alternatives : ∫cos2x-1cos2x+1⋅dx = - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Choose the correct options from the given alternatives :

`int (cos2x - 1)/(cos2x + 1)*dx` =

विकल्प

  • tan x – x + c

  • x + tan x + c

  • x – tan x + c

  • – x – cot x + c

MCQ
Advertisements

उत्तर

x – tan x + c

[ Hint : `int (cos2x - 1)/(cos2x + 1)*dx`

= `int (-(1 - cos2x))/(1 + cos^2x)*dx`

= `int (-2sin^2x)/(2cos^2x)*dx`

= `int (sec^2x - 1)*dx`

= – tan x + x + c.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Miscellaneous Exercise 3 [पृष्ठ १५०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.19 | पृष्ठ १५०

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Find `int((3sintheta-2)costheta)/(5-cos^2theta-4sin theta)d theta`.


Integrate the functions:

`(log x)^2/x`


Integrate the functions:

`e^(2x+3)`


Integrate the functions:

sec2(7 – 4x)


Integrate the functions:

`sin x/(1+ cos x)`


Integrate the functions:

`1/(1 - tan x)`


Integrate the functions:

`sqrt(tanx)/(sinxcos x)`


Integrate the functions:

`((x+1)(x + logx)^2)/x`


Evaluate : `∫1/(3+2sinx+cosx)dx`


Evaluate: `int 1/(x(x-1)) dx`


Write a value of

\[\int x^2 \sin x^3 \text{ dx }\]

Write a value of

\[\int \tan^3 x \sec^2 x \text{ dx }\].

 


Write a value of

\[\int\frac{\cos x}{3 + 2 \sin x}\text{  dx}\]

Write a value of\[\int\frac{\cos x}{\sin x \log \sin x} dx\]

 


Write a value of\[\int\frac{\sin x}{\cos^3 x} \text{ dx }\]


Write a value of\[\int\frac{1}{x \left( \log x \right)^n} \text { dx }\].


\[If \int e^x \left( \tan x + 1 \right)\text{ sec  x  dx } = e^x f\left( x \right) + C, \text{ then  write  the value  of  f}\left( x \right) .\]

 

 


\[\int x \sin^3 x\ dx\]

Evaluate : `int ("e"^"x" (1 + "x"))/("cos"^2("x""e"^"x"))"dx"`


 Show that : `int _0^(pi/4) "log" (1+"tan""x")"dx" = pi /8 "log"2`


Integrate the following w.r.t. x : `int x^2(1 - 2/x)^2 dx`


Evaluate the following integral: 

`int(4x + 3)/(2x + 1).dx`


Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`


If `f'(x) = x - (3)/x^3, f(1) = (11)/(2)`, find f(x)


Evaluate the following : `int (1)/(5 - 4x - 3x^2).dx`


Choose the correct options from the given alternatives : 

`int dx/(cosxsqrt(sin^2x - cos^2x))*dx` =


Evaluate the following.

`int 1/(4"x"^2 - 1)` dx


Evaluate the following.

`int 1/(7 + 6"x" - "x"^2)` dx


Evaluate the following.

`int 1/(sqrt("x"^2 + 4"x"+ 29))` dx


State whether the following statement is True or False.

If `int x  "e"^(2x)` dx is equal to `"e"^(2x)` f(x) + c, where c is constant of integration, then f(x) is `(2x - 1)/2`.


Evaluate `int 1/((2"x" + 3))` dx


`int cot^2x  "d"x`


`int(log(logx))/x  "d"x`


State whether the following statement is True or False:

`int"e"^(4x - 7)  "d"x = ("e"^(4x - 7))/(-7) + "c"`


State whether the following statement is True or False:

`int sqrt(1 + x^2) *x  "d"x = 1/3(1 + x^2)^(3/2) + "c"`


The integral `int ((1 - 1/sqrt(3))(cosx - sinx))/((1 + 2/sqrt(3) sin2x))dx` is equal to ______.


Find `int dx/sqrt(sin^3x cos(x - α))`.


Find `int (x + 2)/sqrt(x^2 - 4x - 5) dx`.


if `f(x) = 4x^3 - 3x^2 + 2x +k, f (0) = - 1 and f (1) = 4, "find " f(x)`


Evaluate the following.

`int 1/(x^2+4x-5)  dx`


Prove that:

`int 1/sqrt(x^2 - a^2) dx = log |x + sqrt(x^2 - a^2)| + c`.


`int x^3 e^(x^2) dx`


Evaluate.

`int (5x^2 - 6x + 3)/(2x - 3) dx`


If f ′(x) = 4x3 − 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate `int (1 + "x" + "x"^2/(2!))`dx


Evaluate `int1/(x(x-1))dx`


Evaluate the following.

`int1/(x^2+4x-5)dx`


Evaluate `int (5x^2 - 6x + 3)/(2x - 3) dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×