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Choose the correct options from the given alternatives : ∫cos2x-1cos2x+1⋅dx =

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Question

Choose the correct options from the given alternatives :

`int (cos2x - 1)/(cos2x + 1)*dx` =

Options

  • tan x – x + c

  • x + tan x + c

  • x – tan x + c

  • – x – cot x + c

MCQ
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Solution

x – tan x + c

[ Hint : `int (cos2x - 1)/(cos2x + 1)*dx`

= `int (-(1 - cos2x))/(1 + cos^2x)*dx`

= `int (-2sin^2x)/(2cos^2x)*dx`

= `int (sec^2x - 1)*dx`

= – tan x + x + c.

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Chapter 3: Indefinite Integration - Miscellaneous Exercise 3 [Page 150]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.19 | Page 150

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