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Question
Evaluate the following integrals:
tan2x dx
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Solution
1 + tan2x = sec2x
tan2x = sec2x – 1
`inttan^2 xdx = int(sec^2 x- 1) dx`
split the integral into two parts:
`intsec^2xdx - int 1dx`
∫sec2 x dx = tanx
∫1 dx = x
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