English

Integrate the following functions w.r.t. x : ∫1cosx-3sinx.dx

Advertisements
Advertisements

Question

Integrate the following functions w.r.t. x : `int (1)/(cosx - sqrt(3)sinx).dx`

Sum
Advertisements

Solution

Let I = `int (1)/(cosx - sqrt(3)sinx).dx`

I = `int ((1)/(2))/(1/2.cosx - sqrt(3)/2sinx).dx`

= `(1)/(2) int (1)/( cos  pi/(3). cosx  - sin  pi/(3).sin x)dx`

= `(1)/(2) int (1)/cos (pi/3 + x).dx`

= `(1)/(2) int sec(x + pi/3).dx`

= `(1)/(2)log|sec(x + pi/3) + tan(x + pi/3)| + c`.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Exercise 3.2 (B) [Page 123]

APPEARS IN

RELATED QUESTIONS

Evaluate :`intxlogxdx`


Integrate the functions:

`1/(x + x log x)`


Integrate the functions:

`xsqrt(1+ 2x^2)`


Integrate the functions:

tan2(2x – 3)


Integrate the functions:

`cos sqrt(x)/sqrtx`


Integrate the functions:

`cos x /(sqrt(1+sinx))`


Integrate the functions:

`(1+ log x)^2/x`


\[\int\sqrt{3 + 2x - x^2} \text{ dx}\]

Write a value of

\[\int e^x \sec x \left( 1 + \tan x \right) \text{ dx }\]

Write a value of

\[\int e^{\text{ log  sin x  }}\text{ cos x}. \text{ dx}\]

Write a value of\[\int\text{ tan x }\sec^3 x\ dx\]


Write a value of\[\int\left( e^{x \log_e \text{  a}} + e^{a \log_e x} \right) dx\] .


Write a value of\[\int\sqrt{x^2 - 9} \text{ dx}\]


Evaluate the following integrals:

`int(2)/(sqrt(x) - sqrt(x + 3)).dx`


Integrate the following functions w.r.t. x : `(x.sec^2(x^2))/sqrt(tan^3(x^2)`


Integrate the following functions w.r.t. x : `(x^2 + 2)/((x^2 + 1)).a^(x + tan^-1x)`


Integrate the following functions w.r.t. x : `(4e^x - 25)/(2e^x - 5)`


Integrate the following functions w.r.t. x : `(3e^(2x) + 5)/(4e^(2x) - 5)`


Evaluate the following : `int (1)/sqrt(2x^2 - 5).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2sinx).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2 sin2x + 4cos 2x).dx`


Choose the correct options from the given alternatives :

`int (e^(2x) + e^-2x)/e^x*dx` =


Choose the correct alternative from the following.

`int "dx"/(("x" - "x"^2))`= 


`int (x^2 + x - 6)/((x - 2)(x - 1))dx = x` + ______ + c


Evaluate `int (5"x" + 1)^(4/9)` dx


`int sqrt(1 + sin2x)  dx`


`int (7x + 9)^13  "d"x` ______ + c


`int sin^-1 x`dx = ?


`int sec^6 x tan x   "d"x` = ______.


The value of `intsinx/(sinx - cosx)dx` equals ______.


`int dx/(2 + cos x)` = ______.

(where C is a constant of integration)


Find `int (x + 2)/sqrt(x^2 - 4x - 5) dx`.


Evaluate the following.

`int x^3/(sqrt(1+x^4))dx`


Evaluate `int1/(x(x - 1))dx`


Evaluate the following.

`int 1/(x^2 + 4x - 5)dx`


Evaluate:

`int sqrt((a - x)/x) dx`


Evaluate:

`int(sqrt(tanx) + sqrt(cotx))dx`


Evaluate:

`int sin^2(x/2)dx`


`int x^2/sqrt(1 - x^6)dx` = ______.


`int 1/(sin^2x cos^2x)dx` = ______.


`int (cos4x)/(sin2x + cos2x)dx` = ______.


Evaluate `int 1/(x(x-1))dx`


Evaluate `int1/(x(x-1))dx`


If f '(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate the following.

`intx^3/sqrt(1+x^4)dx`


Evaluate `int 1/(x(x-1))dx`


Evaluate `int (5x^2 - 6x + 3)/(2x - 3) dx`


Evaluate:

`intsqrt(sec  x/2 - 1)dx`


`int (x + 1)/(x(1 + xe^x)) dx` is equal to


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×