English

∫ √ 9 − X 2 D X

Advertisements
Advertisements

Question

\[\int\sqrt{9 - x^2}\text{ dx}\]
Sum
Advertisements

Solution

\[\int \sqrt{9 - x^2} \text{ dx}\]
\[ = \int \sqrt{3^2 - x^2} \text{ dx}\]
\[ = \frac{x}{2}\sqrt{3^2 - x^2} + \frac{3^2}{2} \sin^{- 1} \left( \frac{x}{3} \right) + C \left[ \because \int\sqrt{a^2 - x^2} \text{ dx } = \frac{1}{2}x\sqrt{a^2 - x^2} + \frac{1}{2} a^2 \text{ sin}^{- 1} \left( \frac{x}{a} \right) + C \right]\]
\[ = \frac{x}{2}\sqrt{9 - x^2} + \frac{9}{2} \sin^{- 1} \left( \frac{x}{3} \right) + C\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 18: Indefinite Integrals - Exercise 19.28 [Page 154]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 18 Indefinite Integrals
Exercise 19.28 | Q 7 | Page 154

RELATED QUESTIONS

Integrate the functions:

`1/(x + x log x)`


Integrate the functions:

`cos x /(sqrt(1+sinx))`


Integrate the functions:

`(sin x)/(1+ cos x)^2`


\[\int\sqrt{3 + 2x - x^2} \text{ dx}\]

\[\int\sqrt{16 x^2 + 25} \text{ dx}\]

Write a value of\[\int e^{ax} \sin\ bx\ dx\]


`int "dx"/(9"x"^2 + 1)= ______. `


Evaluate the following integrals : `int (cos2x)/(sin^2x.cos^2x)dx`


Evaluate the following integrals: `int sin 4x cos 3x dx`


Evaluate the following integrals:

`int (sin4x)/(cos2x).dx`


Integrate the following functions w.r.t. x : `(logx)^n/x`


Integrate the following functions w.r.t.x:

`(5 - 3x)(2 - 3x)^(-1/2)`


Integrate the following functions w.r.t. x : `x^2/sqrt(9 - x^6)`


Integrate the following functions w.r.t. x : `(4e^x - 25)/(2e^x - 5)`


Integrate the following functions w.r.t. x : `(20 + 12e^x)/(3e^x + 4)`


Integrate the following functions w.r.t. x : `(sin6x)/(sin 10x sin 4x)`


Evaluate the following : `int sqrt((9 + x)/(9 - x)).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2sin x - cosx)dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2 sin2x + 4cos 2x).dx`


Evaluate the following integrals :  `int (3x + 4)/sqrt(2x^2 + 2x + 1).dx`


Evaluate `int (3"x"^2 - 5)^2` dx


Evaluate the following.

`int 1/(x(x^6 + 1))` dx 


Evaluate the following.

`int 1/(sqrt(3"x"^2 - 5))` dx


Evaluate: `int (2"e"^"x" - 3)/(4"e"^"x" + 1)` dx


`int 1/(xsin^2(logx))  "d"x`


`int cos^7 x  "d"x`


`int (cos x)/(1 - sin x) "dx" =` ______.


`int ("d"x)/(x(x^4 + 1))` = ______.


The value of `int (sinx + cosx)/sqrt(1 - sin2x) dx` is equal to ______.


`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`


Evaluated the following

`int x^3/ sqrt (1 + x^4 )dx`


If f ′(x) = 4x3 − 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x)


Evaluate the following

`int x^3/sqrt(1+x^4) dx`


Evaluate:

`int(sqrt(tanx) + sqrt(cotx))dx`


If f'(x) = 4x3- 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate `int1/(x(x-1))dx` 


Evaluate.

`int (5x^2 -6x + 3)/(2x -3)dx`


Which standard substitution is used for \[\sqrt{x^2+\mathrm{a}^2}\], \[\frac{1}{\sqrt{x^2+\mathrm{a}^2}}\], or \[x^2+\mathrm{a}^2\]?


Which substitution is appropriate for \[\sqrt{\frac{x}{x-a}}\], \[\sqrt{\frac{x-a}{x}}\], \[\sqrt{x(x-\mathrm{a})}\], or \[\frac{1}{\sqrt{x(x-\mathrm{a})}}\]?


After putting \[t=\cos x\], which integral is obtained from \[\int\sin^2x\cos^2x(\sin x)\,dx\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×