Advertisements
Advertisements
Question
Integrate the following functions w.r.t. x : `int (1)/(2 + cosx - sinx).dx`
Advertisements
Solution
Let I = `int (1)/(2 + cosx - sinx).dx`
Put `tan (x/2)` = t
∴ x 2 tan–1 t
∴ dx = `(2dt)/(1 + t^2) and sin x = (2t)/(1 + t^2), cosx = (1 - t^2)/(1 + t^2)`
∴ I = `int (1)/(2 + ((1 - t^2)/(1 + t^2)) - ((2t)/(1 + t^2))).(2dt)/(1 + t^2)`
= `int (1 + t^2)/(2 + 2t^2 + 1 - t^2 - 2t).(2dt)/(1 + t^2)`
= `2 int (1)/(t^2 - 2t + 3)dt`
= `2 int (1)/((t^2 - 2t + 1) + 2)dt`
= `2 int (1)/((t - 1)^2 + (sqrt(2))^2).dt`
= `2 xx (1)/sqrt(2)tan^-1 ((t - 1)/sqrt(2)) + c`
= `sqrt(2)tan^-1[(tan(x/2) - 1)/sqrt(2)] + c`.
APPEARS IN
RELATED QUESTIONS
Evaluate : `int(x-3)sqrt(x^2+3x-18) dx`
Integrate the functions:
(4x + 2) `sqrt(x^2 + x +1)`
Integrate the functions:
`sqrt(sin 2x) cos 2x`
Integrate the functions:
`cos x /(sqrt(1+sinx))`
Integrate the functions:
`(1+ log x)^2/x`
`(10x^9 + 10^x log_e 10)/(x^10 + 10^x) dx` equals:
Evaluate `int 1/(3+ 2 sinx + cosx) dx`
Write a value of
Write a value of\[\int\frac{\sin x - \cos x}{\sqrt{1 + \sin 2x}} \text{ dx}\]
Write a value of\[\int\sqrt{9 + x^2} \text{ dx }\].
Evaluate : `int ("e"^"x" (1 + "x"))/("cos"^2("x""e"^"x"))"dx"`
Evaluate the following integrals : `int (sin2x)/(cosx)dx`
Evaluate the following integrals:
`int (cos2x)/sin^2x dx`
Evaluate the following integrals : `intsqrt(1 - cos 2x)dx`
Evaluate the following integrals: `int(x - 2)/sqrt(x + 5).dx`
Evaluate the following integrals:
`int(2)/(sqrt(x) - sqrt(x + 3)).dx`
Integrate the following functions w.r.t. x : `(logx)^n/x`
Integrate the following functions w.r.t.x:
`(2sinx cosx)/(3cos^2x + 4sin^2 x)`
Integrate the following functions w.r.t. x : `(7 + 4 + 5x^2)/(2x + 3)^(3/2)`
Integrate the following functions w.r.t. x : `sin(x - a)/cos(x + b)`
Integrate the following functions w.r.t. x : `(3e^(2x) + 5)/(4e^(2x) - 5)`
Integrate the following functions w.r.t.x:
cos8xcotx
Evaluate the following : `int (1)/sqrt(2x^2 - 5).dx`
Integrate the following functions w.r.t. x : `int (1)/(3 + 2sin x - cosx)dx`
Evaluate `int 1/("x" ("x" - 1))` dx
Evaluate the following.
`int "x" sqrt(1 + "x"^2)` dx
Evaluate the following.
`int (2"e"^"x" + 5)/(2"e"^"x" + 1)`dx
Evaluate the following.
`int 1/("x"^2 + 4"x" - 5)` dx
Evaluate the following.
`int 1/("a"^2 - "b"^2 "x"^2)` dx
`int ("x + 2")/(2"x"^2 + 6"x" + 5)"dx" = "p" int (4"x" + 6)/(2"x"^2 + 6"x" + 5) "dx" + 1/2 int "dx"/(2"x"^2 + 6"x" + 5)`, then p = ?
State whether the following statement is True or False.
The proper substitution for `int x(x^x)^x (2log x + 1) "d"x` is `(x^x)^x` = t
`int ((x + 1)(x + log x))^4/(3x) "dx" =`______.
`int (cos x)/(1 - sin x) "dx" =` ______.
`int(sin2x)/(5sin^2x+3cos^2x) dx=` ______.
If f'(x) = `x + 1/x`, then f(x) is ______.
If `int(cosx - sinx)/sqrt(8 - sin2x)dx = asin^-1((sinx + cosx)/b) + c`. where c is a constant of integration, then the ordered pair (a, b) is equal to ______.
`int (logx)^2/x dx` = ______.
Find `int (x + 2)/sqrt(x^2 - 4x - 5) dx`.
Evaluate `int (1+x+x^2/(2!))dx`
Evaluate the following.
`int 1/(x^2 + 4x - 5)dx`
Evaluate:
`int(sqrt(tanx) + sqrt(cotx))dx`
Evaluate `int 1/(x(x-1))dx`
Evaluate:
`int(5x^2-6x+3)/(2x-3)dx`
Evaluate the following.
`intx^3/sqrt(1+x^4)dx`
Evaluate the following.
`int "x"^3/sqrt(1 + "x"^4)` dx
Evaluate the following.
`int1/(x^2+4x-5)dx`
