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Evaluate the following integrals : ∫cos2xsin2x.cos2xdx

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Question

Evaluate the following integrals : `int (cos2x)/(sin^2x.cos^2x)dx`

Sum
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Solution

`int (cos2x)/(sin^2x.cos^2x)dx`

= `int(cos^2x - sin^2x)/(sin^2x.cos^2x)dx`

= `int(1/sin^2x - 1/cos^2x)dx`

= `int "cosec"^2x dx - int sec^2 x  dx`

= – cot x – tan x + c.

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Chapter 3: Indefinite Integration - Exercise 3.1 [Page 102]

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