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Evaluate the following integrals : ∫cos2xsin2x.cos2xdx - Mathematics and Statistics

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प्रश्न

Evaluate the following integrals : `int (cos2x)/(sin^2x.cos^2x)dx`

योग
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उत्तर

`int (cos2x)/(sin^2x.cos^2x)dx`

= `int(cos^2x - sin^2x)/(sin^2x.cos^2x)dx`

= `int(1/sin^2x - 1/cos^2x)dx`

= `int "cosec"^2x dx - int sec^2 x  dx`

= – cot x – tan x + c.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.1 [पृष्ठ १०२]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.1 | Q 2.05 | पृष्ठ १०२

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