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Integrate the functions: x9-4x2

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प्रश्न

Integrate the functions:

`x/(9 - 4x^2)`

योग
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उत्तर

Let `I = int x/(9 - 4x^2)` dx

Put 9 - 4x2 = t

⇒ -8x dx = dt

∴ `I = -1/8 int dt/t`

`= -1/8 log |t| + C`

`= 1/8 log  1/ |t| + C`

`= 1/8 log  1/ (|9 - 4x^2|) +C`

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अध्याय 7: Integrals - Exercise 7.2 [पृष्ठ ३०४]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.2 | Q 15 | पृष्ठ ३०४

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