हिंदी

Evaluate the following: ∫125-9x2⋅dx

Advertisements
Advertisements

प्रश्न

Evaluate the following:

`int (1)/(25 - 9x^2)*dx`

मूल्यांकन
Advertisements

उत्तर

I = `int (1)/(25 - 9x^2)*dx`

= `int(1)/(5^2 - (3x)^2)*dx`

= `(1)/(2(5))log |(5 + 3x)/(5 - 3x)|*(1)/(3) + c`

= `(1)/(30)log |(5 + 3x)/(5 - 3x)| + c`

Alternative Method:

`int (1)/(25 - 9x^2)*dx`

= `(1)/(9) int (1)/((25)/(9)x^2)*dx`

= `(1)/(9) int (1)/((5/3)^2 - x^2)*dx`

= `(1)/(9) xx (1)/(2 xx 5/3)log|(5/3 + x)/(5 / 3 - x)|+ c`

= `(1)/(30)log|(5 + 3x)/(5 - 3x)| + c`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.2 (B) [पृष्ठ १२३]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.2 (B) | Q 1.02 | पृष्ठ १२३

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Integrate the functions:

`x/(sqrt(x+ 4))`, x > 0 


Integrate the functions:

`sin x/(1+ cos x)`


Integrate the functions:

`sqrt(tanx)/(sinxcos x)`


Write a value of

\[\int\frac{1 + \cot x}{x + \log \sin x} \text{ dx }\]

Write a value of\[\int\frac{\sec^2 x}{\left( 5 + \tan x \right)^4} dx\]


Write a value of\[\int\frac{\sin x + \cos x}{\sqrt{1 + \sin 2x}} dx\]


Write a value of\[\int\frac{\cos x}{\sin x \log \sin x} dx\]

 


Evaluate the following integrals : `int (cos2x)/(sin^2x.cos^2x)dx`


Evaluate the following integrals : `int sqrt(1 + sin 2x) dx`


Integrate the following functions w.r.t. x : sin4x.cos3x


Integrate the following functions w.r.t. x : `((x - 1)^2)/(x^2 + 1)^2`


Integrate the following function w.r.t. x:

`(10x^9 +10^x.log10)/(10^x + x^10)`


Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`


Integrate the following functions w.r.t. x : `(3e^(2x) + 5)/(4e^(2x) - 5)`


Integrate the following functions w.r.t.x:

cos8xcotx


Evaluate the following : `int (1)/(7 + 2x^2).dx`


Evaluate the following : `int sqrt((10 + x)/(10 - x)).dx`


Evaluate the following integrals : `int (2x + 3)/(2x^2 + 3x - 1).dx`


Evaluate the following integrals :  `int (3x + 4)/sqrt(2x^2 + 2x + 1).dx`


Choose the correct options from the given alternatives :

`int sqrt(cotx)/(sinx*cosx)*dx` =


Integrate the following with respect to the respective variable:

`x^7/(x + 1)`


Evaluate `int (-2)/(sqrt("5x" - 4) - sqrt("5x" - 2))`dx


Evaluate `int (3"x"^3 - 2sqrt"x")/"x"` dx


Evaluate the following.

`int 1/("x" log "x")`dx


Evaluate the following.

`int 1/("a"^2 - "b"^2 "x"^2)` dx


Evaluate the following.

`int 1/(sqrt(3"x"^2 - 5))` dx


`int sqrt(1 + "x"^2) "dx"` =


State whether the following statement is True or False.

The proper substitution for `int x(x^x)^x (2log x + 1)  "d"x` is `(x^x)^x` = t


Evaluate `int (5"x" + 1)^(4/9)` dx


Evaluate: ∫ |x| dx if x < 0


`int e^x/x [x (log x)^2 + 2 log x]` dx = ______________


`int (2(cos^2 x - sin^2 x))/(cos^2 x + sin^2 x)` dx = ______________


`int x/(x + 2)  "d"x`


`int sqrt(("e"^(3x) - "e"^(2x))/("e"^x + 1))  "d"x`


Evaluate  `int"e"^x (1/x - 1/x^2)  "d"x`


`int (x^2 + 1)/(x^4 - x^2 + 1)`dx = ?


`int dx/(1 + e^-x)` = ______


`int(5x + 2)/(3x - 4) dx` = ______


General solution of `(x + y)^2 ("d"y)/("d"x) = "a"^2, "a" ≠ 0` is ______. (c is arbitrary constant)


`int ("d"x)/(x(x^4 + 1))` = ______.


`int ("d"x)/(sinx cosx + 2cos^2x)` = ______.


If `int(cosx - sinx)/sqrt(8 - sin2x)dx = asin^-1((sinx + cosx)/b) + c`. where c is a constant of integration, then the ordered pair (a, b) is equal to ______.


`int (sin  (5x)/2)/(sin  x/2)dx` is equal to ______. (where C is a constant of integration).


`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`


Evaluated the following

`int x^3/ sqrt (1 + x^4 )dx`


Evaluate the following.

`int 1/(x^2 + 4x - 5)  dx`


If f'(x) = 4x3 - 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate the following.

`int1/(x^2 + 4x-5)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×