हिंदी

Integrate the following function w.r.t. x: 10x9+10x.log1010x+x10 - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Integrate the following function w.r.t. x:

`(10x^9 +10^x.log10)/(10^x + x^10)`

योग
Advertisements

उत्तर

Let I = `int (10x^9 + 10^x.log10)/(10^x + x^10).dx`

Put 10x + x10 = t

∴ (10x. log 10 + 10x9).dx = dt

∴ I = `int(1)/t dt` = log | t | + c

= log | 10x + x10 | + c

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.2 (A) [पृष्ठ ११०]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.2 (A) | Q 1.17 | पृष्ठ ११०

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Evaluate : `int (sinx)/sqrt(36-cos^2x)dx`


Find : `int((2x-5)e^(2x))/(2x-3)^3dx`


Integrate the functions:

sin x ⋅ sin (cos x)


Integrate the functions:

`xsqrt(x + 2)`


Integrate the functions:

`1/(x(log x)^m),  x > 0, m ne 1`


Integrate the functions:

`cos sqrt(x)/sqrtx`


Integrate the functions:

`sin x/(1+ cos x)`


Solve:

dy/dx = cos(x + y)


\[\int\sqrt{16 x^2 + 25} \text{ dx}\]

Write a value of

\[\int x^2 \sin x^3 \text{ dx }\]

Write a value of

\[\int \tan^6 x \sec^2 x \text{ dx }\] .

Write a value of\[\int\frac{\sec^2 x}{\left( 5 + \tan x \right)^4} dx\]


 Show that : `int _0^(pi/4) "log" (1+"tan""x")"dx" = pi /8 "log"2`


Find : ` int  (sin 2x ) /((sin^2 x + 1) ( sin^2 x + 3 ) ) dx`


Integrate the following w.r.t. x : `(3x^3 - 2x + 5)/(xsqrt(x)`


Evaluate the following integrals: `int (2x - 7)/sqrt(4x - 1).dx`


Integrate the following functions w.r.t. x : `(e^(2x) + 1)/(e^(2x) - 1)`


Integrate the following functions w.r.t. x : e3logx(x4 + 1)–1 


Integrate the following functions w.r.t. x : sin5x.cos8x


Integrate the following functions w.r.t. x : `int (1)/(4 - 5cosx).dx`


Integrate the following functions w.r.t. x : `int (1)/(cosx - sqrt(3)sinx).dx`


Evaluate the following integrals:

`int (2x + 1)/(x^2 + 4x - 5).dx`


Evaluate the following integral:

`int (3cosx)/(4sin^2x + 4sinx - 1).dx`


If f '(x) = `"x"^2/2 - "kx" + 1`, f(0) = 2 and f(3) = 5, find f(x).


Evaluate the following.

`int ("e"^"x" + "e"^(- "x"))^2 ("e"^"x" - "e"^(-"x"))`dx


Choose the correct alternative from the following.

`int "x"^2 (3)^("x"^3) "dx"` =


`int ("x + 2")/(2"x"^2 + 6"x" + 5)"dx" = "p" int (4"x" + 6)/(2"x"^2 + 6"x" + 5) "dx" + 1/2 int "dx"/(2"x"^2 + 6"x" + 5)`, then p = ?


Evaluate `int 1/((2"x" + 3))` dx


Evaluate: `int 1/(2"x" + 3"x" log"x")` dx


Evaluate: `int "x" * "e"^"2x"` dx


`int 2/(sqrtx - sqrt(x + 3))` dx = ________________


`int ("e"^(3x))/("e"^(3x) + 1)  "d"x`


`int1/(4 + 3cos^2x)dx` = ______ 


`int ((x + 1)(x + log x))^4/(3x) "dx" =`______.


Evaluate `int_-a^a f(x) dx`, where f(x) = `9^x/(1 + 9^x)`.


`int secx/(secx - tanx)dx` equals ______.


Evaluated the following

`int x^3/ sqrt (1 + x^4 )dx`


Evaluate.

`int(5"x"^2 - 6"x" + 3)/(2"x" - 3)  "dx"`


Evaluate:

`int 1/(1 + cosα . cosx)dx`


`int 1/(sin^2x cos^2x)dx` = ______.


Evaluate:

`int(cos 2x)/sinx dx`


Evaluate the following:

`int x^3/(sqrt(1+x^4))dx`


Evaluate `int(1+x+x^2/(2!))dx`


Evaluate the following.

`int "x"^3/sqrt(1 + "x"^4)` dx


Evaluate the following.

`int1/(x^2 + 4x - 5)  dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×