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Integrate the following functions w.r.t. x : ∫12sin2x-3dx

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प्रश्न

Integrate the following functions w.r.t. x : `int (1)/(2sin 2x - 3)dx`

योग
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उत्तर

Let I = `int (1)/(2sin 2x - 3)dx`

Put tan x = t
∴ x = tan–1 t

∴ dx = `dt/(1 + t^2) and sin 2x = (2t)/(1 + t^2)`

∴ I = `int(1)/(2((2t)/(1 + t^2)) - 3).dt/(1 + t^2)`

= `int (1 + t^2)/(4t - 3 - 3t^2).dt/(1 + t^2)`

= `int (1)/(-3t^2 + 4t - 3)dt`

= `(1)/(3) int (1)/(t^2 - 4/3t + 1)dt`

= `-(1)/(3)  int (1)/((t^2 - 4/3t + 4/9) - (4)/(9) + 1)dt`

= `-(1)/(3) int (1)/((t - 2/3)^2 + (sqrt(5)/3)^2)dt`

= `-(1)/(3) xx (1)/((sqrt(5)/3))tan^-1 ((t - 2/3)/(sqrt(5)/3)) + c`

= `-(1)/sqrt(5)tan^-1 ((3t - 2)/sqrt(5)) + c`

= `-(1)/sqrt(5)tan^-1((3tan x - 2)/(sqrt(5))) + c`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.2 (B) [पृष्ठ १२३]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.2 (B) | Q 2.6 | पृष्ठ १२३

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