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Evaluate ∫x - 1x + 4 dx

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प्रश्न

Evaluate `int "x - 1"/sqrt("x + 4")` dx

योग
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उत्तर

Let I = `int "x - 1"/sqrt("x + 4")` dx

= `int (("x + 4") - 5)/sqrt("x + 4")` dx

= `int (sqrt"x + 4" - 5/(sqrt "x + 4"))` dx

`= int [("x + 4")^(1/2) - 5("x + 4")^(- 1/2)]` dx

`= ("x + 4")^(3/2)/(3/2) - 5 ("x + 4")^(1/2)/(1/2)` + c

∴ I = `2/3 ("x + 4")^(3/2) - 10 sqrt("x + 4")` + c

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अध्याय 5: Integration - MISCELLANEOUS EXERCISE - 5 [पृष्ठ १३८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 5 Integration
MISCELLANEOUS EXERCISE - 5 | Q IV. 1) iv) | पृष्ठ १३८

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