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प्रश्न
`int (sin4x)/(cos 2x) "d"x`
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उत्तर
`int (sin4x)/(cos 2x) "d"x`
= `int (sin2(2x))/(cos2x) "d"x`
= `int (2sin2x cos2x)/(cos 2x) "d"x`
= `2 int sin 2x "d"x`
= `2*((-cos 2x))/2 + c`
= – cos 2x + c
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