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प्रश्न
Evaluate :`intxlogxdx`
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उत्तर
`intudv = uv-intvdu`
Choosing u = logx and dv = xdx
`du = 1/xdx `
`v = x^2/2`
`:.intxlogxdx=logx x^2/2-intx^2/2 1/xdx`
`=x^2/2logx-1/2intxdx`
`=x^2/2logx-1/2 x^2/2+C`
`=x^2/2logx-x^2/4+C`
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