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Evaluate: ∫ X 3 − 1 X 2 D X

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प्रश्न

Evaluate:  \[\int\frac{x^3 - 1}{x^2} \text{ dx}\]

योग
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उत्तर

\[\int\left( \frac{x^3 - 1}{x^2} \right) dx\]
\[ = \int\left( \frac{x^3}{x^2} - \frac{1}{x^2} \right)dx\]
\[ = \int\left( x - x^{- 2} \right)dx\]
\[ = \frac{x^2}{2} - \frac{x^{- 2 + 1}}{- 2 + 1} + C\]
\[ = \frac{x^2}{2} + \frac{1}{x} + C\]

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अध्याय 18: Indefinite Integrals - Very Short Answers [पृष्ठ १९८]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 18 Indefinite Integrals
Very Short Answers | Q 48 | पृष्ठ १९८

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