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Evaluate: ∫ X 3 − X 2 + X − 1 X − 1 D X - Mathematics

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प्रश्न

Evaluate: \[\int\frac{x^3 - x^2 + x - 1}{x - 1} \text{ dx }\]

योग
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उत्तर

\[\int\left( \frac{x^3 - x^2 + x - 1}{x - 1} \right) dx\]
\[ = \int\left( \frac{x^2 \left( x - 1 \right) + 1\left( x - 1 \right)}{\left( x - 1 \right)} \right)dx\]
\[ = \int\frac{\left( x^2 + 1 \right) \left( x - 1 \right)}{\left( x - 1 \right)}dx\]
\[ = \int\left( x^2 + 1 \right) dx\]
\[ = \frac{x^3}{3} + x + C\]

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अध्याय 19: Indefinite Integrals - Very Short Answers [पृष्ठ १९८]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Very Short Answers | Q 49 | पृष्ठ १९८

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