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∫logxx dx

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प्रश्न

`int logx/x  "d"x`

योग
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उत्तर

Put log x = t

∴ `1/x  "d"x` = dt

∴ `int logx/x  "d"x = int "t"  "dt"`

= `"t"^2/2 + "c"`

 `((log x)^2)/2 + "c"`

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अध्याय 2.3: Indefinite Integration - Very Short Answers

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