हिंदी

Evaluate the following integrals : ∫cos2x.dx

Advertisements
Advertisements

प्रश्न

Evaluate the following integrals : `int cos^2x.dx`

योग
Advertisements

उत्तर

Recall the identity cos 2x = 2 cos2x – 1, which gives

`cos^2x = (1 + cos2x)/(2)`

Therefore, `int cos^2 x.dx`

= `(1)/(2)int (1 + cos 2x).dx`

= `(1)/(2)int dx + (1)/(2) int cos 2x .dx`

= `x/(2) + (1)/(4)sin 2x + C`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.1 [पृष्ठ १०२]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.1 | Q 3.08 | पृष्ठ १०२

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Evaluate : `int (sinx)/sqrt(36-cos^2x)dx`


Evaluate :

`∫(x+2)/sqrt(x^2+5x+6)dx`


 
 

Evaluate :

`int1/(sin^4x+sin^2xcos^2x+cos^4x)dx`

 
 

Integrate the functions:

`1/(x + x log x)`


Integrate the functions:

`cos sqrt(x)/sqrtx`


Integrate the functions:

`sin x/(1+ cos x)`


Write a value of

\[\int\frac{\cos x}{3 + 2 \sin x}\text{  dx}\]

 Write a valoue of \[\int \sin^3 x \cos x\ dx\]

 


Write a value of\[\int\frac{1}{1 + 2 e^x} \text{ dx }\].


Write a value of\[\int e^x \left( \frac{1}{x} - \frac{1}{x^2} \right) dx\] .


Write a value of\[\int\sqrt{4 - x^2} \text{ dx }\]


Write a value of\[\int\sqrt{x^2 - 9} \text{ dx}\]


The value of \[\int\frac{1}{x + x \log x} dx\] is


Integrate the following w.r.t. x : x3 + x2 – x + 1


Evaluate the following integrals:

`int (cos2x)/sin^2x dx` 


Evaluate the following integrals : `int (cos2x)/(sin^2x.cos^2x)dx`


Evaluate the following integrals : `int sqrt(1 + sin 2x) dx`


Evaluate the following integrals : `int (3)/(sqrt(7x - 2) - sqrt(7x - 5)).dx`


Integrate the following functions w.r.t. x : `(x^2 + 2)/((x^2 + 1)).a^(x + tan^-1x)`


Integrate the following functions w.r.t. x : `(1)/(4x + 5x^-11)`


Integrate the following functions w.r.t. x : `(1)/(x.logx.log(logx)`.


Integrate the following functions w.r.t. x : `cosx/sin(x - a)`


Integrate the following functions w.r.t. x: 

`(1)/(sinx.cosx + 2cos^2x)`


Evaluate the following : `int sqrt((2 + x)/(2 - x)).dx`


Evaluate the following : `int sqrt((10 + x)/(10 - x)).dx`


Evaluate the following integral:

`int (3cosx)/(4sin^2x + 4sinx - 1).dx`


Choose the correct options from the given alternatives :

`int (e^x(x - 1))/x^2*dx` =


Choose the correct options from the given alternatives :

`int (e^(2x) + e^-2x)/e^x*dx` =


Evaluate the following.

`int "x" sqrt(1 + "x"^2)` dx


Evaluate the following.

`int 1/(x(x^6 + 1))` dx 


Evaluate the following.

`int 1/(4x^2 - 20x + 17)` dx


Evaluate the following.

`int 1/(sqrt("x"^2 + 4"x"+ 29))` dx


Fill in the Blank.

`int (5("x"^6 + 1))/("x"^2 + 1)` dx = x4 + ______ x3 + 5x + c


Evaluate: If f '(x) = `sqrt"x"` and f(1) = 2, then find the value of f(x).


Evaluate: `int "e"^"x" (1 + "x")/(2 + "x")^2` dx


`int (cos2x)/(sin^2x)  "d"x`


`int sqrt(("e"^(3x) - "e"^(2x))/("e"^x + 1))  "d"x`


`int1/(4 + 3cos^2x)dx` = ______ 


If I = `int (sin2x)/(3x + 4cosx)^3 "d"x`, then I is equal to ______.


Evaluate the following.

`int x sqrt(1 + x^2)  dx`


Evaluate the following.

`intx sqrt(1 +x^2)  dx`


`int (cos4x)/(sin2x + cos2x)dx` = ______.


Evaluate the following:

`int (1) / (x^2 + 4x - 5) dx`


Evaluate `int (1 + x + x^2/(2!)) dx`


Evaluate.

`int (5x^2 -6x + 3)/(2x -3)dx`


Evaluate `int(5x^2-6x+3)/(2x-3)dx`


Evaluate the following.

`int1/(x^2+4x-5)dx`


Evaluate the following.

`int1/(x^2 + 4x - 5)dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×