हिंदी

Evaluate the following : ∫2+x2-x.dx

Advertisements
Advertisements

प्रश्न

Evaluate the following : `int sqrt((2 + x)/(2 - x)).dx`

योग
Advertisements

उत्तर

Let I = `int sqrt((2 + x)/(2 - x)).dx`

= `int sqrt((2 + x)/(2 - x) xx (2 + x)/(2 + x)).dx`

= `int (2 + x)/sqrt(4 - x^2).dx`

= `int (2)/sqrt(4 - x^2).dx + int x/sqrt(4 - x^2).dx`

= `2 int (1)/sqrt(2^2 - x^2).dx + (1)/(2) int (2x)/sqrt(4 - x^2).dx`

= I1 + I2                        ...(Let)

I1 = `2 int (1)/sqrt(2^2 - x^2).dx`

= `2 sin^-1 (x/2) + c_1`

In I2, put 4 – x2 = t
∴ – 2x dx =  dt
∴  2x dx = – dt

I2 = `-(1)/(2) int t^(-1/2) dt`

= `-(1)/(2).t^(1/2)/((1/2)) + c_2`

= `- sqrt(4 - x^2) + c_2`

I = `2 sin^-1 (x/2) - sqrt(4 - x^2) + c`.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.2 (B) [पृष्ठ १२३]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.2 (B) | Q 1.08 | पृष्ठ १२३

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Evaluate :

`∫(x+2)/sqrt(x^2+5x+6)dx`


Integrate the functions:

sin (ax + b) cos (ax + b)


Integrate the functions:

`sqrt(ax + b)`


Integrate the functions:

`sin x/(1+ cos x)`


Integrate the functions:

`1/(1 + cot x)`


Evaluate: `int 1/(x(x-1)) dx`


Write a value of

\[\int\frac{a^x}{3 + a^x} \text{ dx}\]

Write a value of\[\int e^x \left( \frac{1}{x} - \frac{1}{x^2} \right) dx\] .


\[If \int e^x \left( \tan x + 1 \right)\text{ sec  x  dx } = e^x f\left( x \right) + C, \text{ then  write  the value  of  f}\left( x \right) .\]

 

 


Evaluate the following integrals : `int (sin2x)/(cosx)dx`


Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`


Integrate the following functions w.r.t. x : `(e^(2x) + 1)/(e^(2x) - 1)`


Integrate the following functions w.r.t. x : `((x - 1)^2)/(x^2 + 1)^2`


Integrate the following functions w.r.t. x : `(x^n - 1)/sqrt(1 + 4x^n)`


Integrate the following functions w.r.t. x:

`x^5sqrt(a^2 + x^2)`


Integrate the following functions w.r.t. x : `(1)/(x(x^3 - 1)`


Integrate the following functions w.r.t. x : `3^(cos^2x) sin 2x`


Evaluate the following : `int sqrt((10 + x)/(10 - x)).dx`


Evaluate the following : `int (1)/(1 + x - x^2).dx`


Evaluate the following : `int (1)/sqrt(x^2 + 8x - 20).dx`


Evaluate the following : `int (1)/sqrt(8 - 3x + 2x^2).dx`


Evaluate the following : `int (1)/(4 + 3cos^2x).dx`


Integrate the following functions w.r.t. x : `int (1)/(2sin 2x - 3)dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2 sin2x + 4cos 2x).dx`


Evaluate `int (3"x"^3 - 2sqrt"x")/"x"` dx


Evaluate the following.

`int ((3"e")^"2t" + 5)/(4"e"^"2t" - 5)`dt


Evaluate the following.

`int 1/("a"^2 - "b"^2 "x"^2)` dx


Evaluate the following.

`int 1/(sqrt("x"^2 -8"x" - 20))` dx


Fill in the Blank.

`int (5("x"^6 + 1))/("x"^2 + 1)` dx = x4 + ______ x3 + 5x + c


Evaluate: `int 1/(sqrt("x") + "x")` dx


Evaluate: `int "e"^"x" (1 + "x")/(2 + "x")^2` dx


`int logx/x  "d"x`


`int 1/(xsin^2(logx))  "d"x`


State whether the following statement is True or False:

`int"e"^(4x - 7)  "d"x = ("e"^(4x - 7))/(-7) + "c"`


General solution of `(x + y)^2 ("d"y)/("d"x) = "a"^2, "a" ≠ 0` is ______. (c is arbitrary constant)


`int (f^'(x))/(f(x))dx` = ______ + c.


Evaluate the following.

`int 1/(x^2 + 4x - 5)dx`


Evaluate the following.

`int x sqrt(1 + x^2)  dx`


Prove that:

`int 1/sqrt(x^2 - a^2) dx = log |x + sqrt(x^2 - a^2)| + c`.


Evaluate `int (1)/(x(x - 1))dx`


Evaluate:

`int sqrt((a - x)/x) dx`


Evaluate `int 1/(x(x-1))dx`


If f'(x) = 4x3- 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Evaluate the following.

`int x^3 e^(x^2) dx`


Evaluate `int1/(x(x-1))dx`


Evaluate:

`intsqrt(sec  x/2 - 1)dx`


`int (x + 1)/(x(1 + xe^x)) dx` is equal to


Which substitution is appropriate for \[\sqrt{\frac{x}{a-x}}\], \[\sqrt{\frac{a-x}{x}}\], \[\sqrt{x(a-x)}\], or \[\frac{1}{\sqrt{x(a-x)}}\]?


After choosing \[u=g(x)\], what is the next step?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×