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Evaluate the following integrals : ∫37x-2-7x-5.dx

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प्रश्न

Evaluate the following integrals : `int (3)/(sqrt(7x - 2) - sqrt(7x - 5)).dx`

योग
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उत्तर

`int (3)/(sqrt(7x - 2) - sqrt(7x - 5)).dx`

= `int (3)/(sqrt(7x - 2) - sqrt(7x - 5)) xx  (sqrt(7x - 2) + sqrt(7x - 5))/(sqrt(7x - 2) + sqrt(7x - 5)).dx`

= `int (3(sqrt(7x - 2) + sqrt(7x - 5)))/((7x - 2) - (7x - 5)).dx`

= `int (sqrt(7x - 2) + sqrt(7x - 5)).dx`

= `int(7x - 2)^(1/2) .dx + int(7x - 5)^(1/2).dx`

= `((7x - 2)^(3/2))/(3/2) xx (1)/(7) + ((7x - 5)^(3/2))/(3/2) xx (1)/(7) + c`

= `(2)/(21)(7x - 2)^(3/2) + (2)/(21)(7x - 5)^(3/2) + c`.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Indefinite Integration - Exercise 3.1 [पृष्ठ १०२]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Indefinite Integration
Exercise 3.1 | Q 3.1 | पृष्ठ १०२

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