हिंदी

Evaluate : ∫sinx/√(36−cos^2x)dx

Advertisements
Advertisements

प्रश्न

Evaluate : `int (sinx)/sqrt(36-cos^2x)dx`

योग
Advertisements

उत्तर

`intsinx/sqrt(36-cos^2x)dx`

Substitute, cosx = t
∴ - sin x dx = dt
∴ sin x dx = - dt
The integral becomes

`int (-dt)/sqrt( 36 - t^2 )`

= `-intdt/sqrt( 6^2 - t^2 )`

= `-sin^-1( t/6 ) + C`

= `-sin^-1 .(cosx/6) + c`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2015-2016 (March)

APPEARS IN

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Find `int((3sintheta-2)costheta)/(5-cos^2theta-4sin theta)d theta`.


Integrate the functions:

`(log x)^2/x`


Integrate the functions:

`x/(9 - 4x^2)`


Integrate the functions:

`e^(2x+3)`


\[\int e^x \sqrt{e^{2x} + 1} \text{ dx}\]

Write a value of

\[\int\frac{a^x}{3 + a^x} \text{ dx}\]

Write a value of\[\int\sqrt{4 - x^2} \text{ dx }\]


\[If \int e^x \left( \tan x + 1 \right)\text{ sec  x  dx } = e^x f\left( x \right) + C, \text{ then  write  the value  of  f}\left( x \right) .\]

 

 


The value of \[\int\frac{\cos \sqrt{x}}{\sqrt{x}} dx\] is


Integrate the following functions w.r.t. x : `(sinx + 2cosx)/(3sinx + 4cosx)`


Integrate the following functions w.r.t. x : `(1)/(2 + 3tanx)`


Integrate the following functions w.r.t. x : `(4e^x - 25)/(2e^x - 5)`


Integrate the following functions w.r.t.x:

cos8xcotx


Integrate the following functions w.r.t. x:

`(sinx cos^3x)/(1 + cos^2x)`


Evaluate the following : `int (1)/sqrt(3x^2 + 5x + 7).dx`


Evaluate the following : `int (1)/(4 + 3cos^2x).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2 sin2x + 4cos 2x).dx`


Evaluate the following integrals:

`int (7x + 3)/sqrt(3 + 2x - x^2).dx`


Evaluate the following.

`int 1/(7 + 6"x" - "x"^2)` dx


Evaluate the following.

`int 1/(sqrt("x"^2 + 4"x"+ 29))` dx


`int cot^2x  "d"x`


To find the value of `int ((1 + logx))/x` dx the proper substitution is ______


`int ((x + 1)(x + log x))^4/(3x) "dx" =`______.


General solution of `(x + y)^2 ("d"y)/("d"x) = "a"^2, "a" ≠ 0` is ______. (c is arbitrary constant)


`int[ tan (log x) + sec^2 (log x)] dx= ` ______


`int ("d"x)/(sinx cosx + 2cos^2x)` = ______.


`int (sin  (5x)/2)/(sin  x/2)dx` is equal to ______. (where C is a constant of integration).


`int 1/(sinx.cos^2x)dx` = ______.


`int dx/(2 + cos x)` = ______.

(where C is a constant of integration)


Evaluate `int(1 + x + x^2/(2!) )dx`


Evaluate.

`int(5"x"^2 - 6"x" + 3)/(2"x" - 3)  "dx"`


Evaluate the following.

`intx sqrt(1 +x^2)  dx`


Evaluate the following.

`int x^3 e^(x^2) dx`


Evaluate the following.

`int x^3/sqrt(1+x^4) dx`


Evaluate the following.

`int (x^3)/(sqrt(1 + x^4)) dx`


Evaluate `int(1+x+x^2/(2!))dx`


Evaluate `int1/(x(x-1))dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×