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Find : ∫x1-x3dx;x∈(0,1). - Mathematics

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प्रश्न

Find : `int sqrt(x/(1 - x^3))dx; x ∈ (0, 1)`.

योग
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उत्तर

Let `x^(3/2)` = t

`\implies` dt = `3/2 x^(1/2) dx`

`int sqrt(x/(1 - x^3))dx = 2/3 int dt/sqrt(1 - t^2)`

= `2/3 sin^-1 (t) + c`

= `2/3 sin^-1 (x^(3/2)) + c`, where 'c' is an arbitrary constant of integration.

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