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प्रश्न
Integrate the following function w.r.t. x:
x9.sec2(x10)
Evaluate:
`intx^9 . sec^2 (x^10) dx`
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उत्तर
Let I = `int x^9 .sec^2(x^10).dx`
Put x10 = t
∴ 10x9dx = dt
∴ x9dx = `(1)/(10)dt`
∴ I = `int sec^2t.dt/(10)`
= `1/10 int sec^2t dt`
= `(1)/(10)tan t+ c`
= `(1)/(10)tan(x^10) + c`
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