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Evaluate the following. ∫20-12ex3ex-4dx

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Question

Evaluate the following.

`int (20 - 12"e"^"x")/(3"e"^"x" - 4)`dx

Sum
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Solution

Let I = `int (20 - 12"e"^"x")/(3"e"^"x" - 4)`dx

Let 20 - 12ex = A(3ex - 4) + B `"d"/"dx"`(3ex - 4)

= 3 Aex - 4A + 3Bex 

∴ 20 - 12ex = (3A + 3B)ex - 4A

Comparing the coefficients of ex and constant term on both sides, we get

- 4A = 20 and 3A + 3B = - 12

Solving these equations, we get

A = -5 and B = 1

∴ I = `int (-5(3"e"^"x" - 4) + 3"e"^"x")/(3"e"^"x" - 4)`dx

`= - 5 int "dx" + int (3"e"^"x")/(3"e"^"x" - 4)` dx

∴ I = - 5x + log `|(3"e"^"x" - 4)|` + c   ....`[int ("f" '("x"))/("f" ("x")) "dx" = log |f ("x")| + "c"]`

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Notes

The answer in the textbook is incorrect.

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Chapter 5: Integration - EXERCISE 5.3 [Page 123]

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