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Question
`int(1 - x)^(-2) dx` = ______.
Options
(1 − x)−1 + c
(1 + x)−1 + c
(1 − x)−1 − 1 + c
(1 − x)−1 + 1 + c
(1 − x)−1 − x + c
(1 − x)−1 + x + c
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Solution
`int(1 - x)^(-2)dx` = (1 − x)−1 + c.
Explanation:
`int(1-x)^-2.dx`
= `(1-x)^(-2+1)/((-2+1)xx(-1)) + c`
= `(1-x)^-1/((-1)(-1)) + c`
= (1 − x)−1 + c
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