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Int"Dx"/9x2+1=

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Question

`int "dx"/(9"x"^2 + 1)= ______. `

Options

  • `1/3 "tan"^-1(2"x") +"c"`

  • `1/3 "tan"^-1"x" +"c"`

  • `1/3 "tan"^-1(3"x") +"c"`

  • `1/3 "tan"^-1(6"x") +"c"`

MCQ
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Solution

`1/3 "tan"^-1(3"x") +"c"`

Let I = `int "dx"/(9"x"^2 + 1)`

= `1/9 int "dx"/(("x"^2) +(1/3)^2)`

= `1/9 1/(1/3) "tan"^-1("x"/(1/3)) + "C"`

`= 1/3 "tan"^-1(3"x") + "c"`

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2018-2019 (March) Set 1

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