English

∫log(logx)x dx

Advertisements
Advertisements

Question

`int(log(logx))/x  "d"x`

Sum
Advertisements

Solution

Let I = `int(log(logx))/x  "d"x`

Put log x = t

∴ `1/x  "d"x` = dt

∴ I = `int log "t"  "dt" = intlog"t"*1  "dt"`

= `log "t" int 1*"dt" - int ["d"/"dt"(log"t") int 1*"dt"]"dt"`

= `log "t"* "t" - int(1/"t" xx "t") "dt"`

= `"t"*log "t" - int "dt"`

= t log t − t + c

= t (log t − 1) + c

∴ I = logx [log (logx) − 1] + c

shaalaa.com
  Is there an error in this question or solution?
Chapter 2.3: Indefinite Integration - Short Answers I

RELATED QUESTIONS

Evaluate :

`∫(x+2)/sqrt(x^2+5x+6)dx`


Integrate the functions:

`(2x)/(1 + x^2)`


Integrate the functions:

`x/(sqrt(x+ 4))`, x > 0 


Integrate the functions:

`x/(e^(x^2))`


Integrate the functions:

`1/(cos^2 x(1-tan x)^2`


Integrate the functions:

cot x log sin x


Integrate the functions:

`(sin x)/(1+ cos x)^2`


Integrate the functions:

`((x+1)(x + logx)^2)/x`


`int (dx)/(sin^2 x cos^2 x)` equals:


\[\int\sqrt{4 x^2 - 5}\text{ dx}\]

Write a value of

\[\int \tan^6 x \sec^2 x \text{ dx }\] .

Write a value of\[\int\left( e^{x \log_e \text{  a}} + e^{a \log_e x} \right) dx\] .


Write a value of\[\int\frac{\sin x - \cos x}{\sqrt{1 + \sin 2x}} \text{ dx}\]


The value of \[\int\frac{\cos \sqrt{x}}{\sqrt{x}} dx\] is


\[\int\frac{\cos^5 x}{\sin x} \text{ dx }\]

Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`


Integrate the following functions w.r.t. x : `(e^(2x) + 1)/(e^(2x) - 1)`


Integrate the following functions w.r.t. x : sin4x.cos3x


Integrate the following functions w.r.t. x : `(1)/(x(x^3 - 1)`


Integrate the following functions w.r.t. x: 

`(1)/(sinx.cosx + 2cos^2x)`


Integrate the following functions w.r.t. x : `(4e^x - 25)/(2e^x - 5)`


Evaluate the following : `int  (1)/(x^2 + 8x + 12).dx`


Integrate the following functions w.r.t. x : `int (1)/(3 + 2sin x - cosx)dx`


Evaluate the following integrals:

`int (7x + 3)/sqrt(3 + 2x - x^2).dx`


Evaluate the following integrals : `int sqrt((e^(3x) - e^(2x))/(e^x + 1)).dx`


Evaluate the following : `int (logx)2.dx`


Choose the correct options from the given alternatives :

`int (e^(2x) + e^-2x)/e^x*dx` =


Integrate the following with respect to the respective variable:

`x^7/(x + 1)`


Evaluate the following.

`int 1/(7 + 6"x" - "x"^2)` dx


Evaluate the following.

`int 1/(sqrt("x"^2 + 4"x"+ 29))` dx


Evaluate: `int 1/(sqrt("x") + "x")` dx


Evaluate: `int "x" * "e"^"2x"` dx


`int (log x)/(log ex)^2` dx = _________


`int  ("e"^x(x - 1))/(x^2)  "d"x` = ______ 


`int ((x + 1)(x + log x))^4/(3x) "dx" =`______.


`int ("d"x)/(sinx cosx + 2cos^2x)` = ______.


`int(log(logx) + 1/(logx)^2)dx` = ______.


`int sqrt(x^2 - a^2)/x dx` = ______.


`int 1/(sinx.cos^2x)dx` = ______.


`int dx/(2 + cos x)` = ______.

(where C is a constant of integration)


`int cos^3x  dx` = ______.


Evaluate the following.

`int(20 - 12"e"^"x")/(3"e"^"x" - 4) "dx"`


if `f(x) = 4x^3 - 3x^2 + 2x +k, f (0) = - 1 and f (1) = 4, "find " f(x)`


Evaluate the following

`int1/(x^2 +4x-5)dx`


Evaluate.

`int (5x^2-6x+3)/(2x-3)dx`


Evaluate `int(1+x+x^2/(2!))dx`


Evaluate the following.

`int 1/ (x^2 + 4x - 5) dx`


Evaluate `int(5x^2-6x+3)/(2x-3)dx`


Evaluate `int (1 + x + x^2/(2!)) dx`


Evaluate `int (5x^2 - 6x + 3)/(2x - 3) dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×