Advertisements
Advertisements
Question
`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`
Options
True
False
Advertisements
Solution
This statement is True.
Explanation:
`int(1-x)^-2.dx`
= `(1-x)^(-2+1)/((-2+1)xx(-1))+"c"`
= `(1-x)^-1/((-1)(-1))+"c"`
= `(1 - x)^-1 + "c"`
APPEARS IN
RELATED QUESTIONS
Integrate the functions:
sec2(7 – 4x)
Integrate the functions:
`1/(1 + cot x)`
Solve:
dy/dx = cos(x + y)
Write a value of
Write a value of\[\int\text{ tan x }\sec^3 x\ dx\]
Write a value of\[\int\frac{\left( \tan^{- 1} x \right)^3}{1 + x^2} dx\]
Integrate the following w.r.t. x:
`2x^3 - 5x + 3/x + 4/x^5`
Integrate the following function w.r.t. x:
x9.sec2(x10)
Integrate the following functions w.r.t. x : `sqrt(tanx)/(sinx.cosx)`
Integrate the following functions w.r.t. x : `int (1)/(cosx - sqrt(3)sinx).dx`
Evaluate the following.
`int 1/(x(x^6 + 1))` dx
Evaluate the following.
`int (20 - 12"e"^"x")/(3"e"^"x" - 4)`dx
Choose the correct alternative from the following.
`int "x"^2 (3)^("x"^3) "dx"` =
`int 1/(xsin^2(logx)) "d"x`
`int (1 + x)/(x + "e"^(-x)) "d"x`
If I = `int (sin2x)/(3x + 4cosx)^3 "d"x`, then I is equal to ______.
`int 1/(a^2 - x^2) dx = 1/(2a) xx` ______.
`int(log(logx) + 1/(logx)^2)dx` = ______.
The value of `int (sinx + cosx)/sqrt(1 - sin2x) dx` is equal to ______.
Evaluate `int(1 + x + x^2/(2!) )dx`
Evaluate the following.
`int 1/(x^2+4x-5) dx`
Evaluate.
`int(5"x"^2 - 6"x" + 3)/(2"x" - 3) "dx"`
Evaluate:
`int sin^2(x/2)dx`
Evaluate.
`int (5x^2-6x+3)/(2x-3)dx`
Evaluate the following.
`int1/(x^2+4x-5) dx`
`int 1/(sin^2x cos^2x)dx` = ______.
Evaluate the following.
`intxsqrt(1+x^2)dx`
Evaluate the following:
`int x^3/(sqrt(1+x^4))dx`
Evaluate the following.
`int1/(x^2 + 4x - 5)dx`
