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∫(1-x)-2 dx = (1-x)-1+c

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Question

`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`

Options

  • True

  • False

MCQ
True or False
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Solution

This statement is True.

Explanation:

`int(1-x)^-2.dx`

= `(1-x)^(-2+1)/((-2+1)xx(-1))+"c"`

= `(1-x)^-1/((-1)(-1))+"c"`

= `(1 - x)^-1 + "c"`

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